Cannot invoke an expression whose type lacks a call signature BinaryTree Type Script
1
I'm trying to implement binary search tree in Type Script using generic types. However I have an issue with adding child in node, because there is an error when parent.leftChild(newNode) - "Cannot invoke an expression whose type is lacks a call signature. Type Node has no compatible call signatures."
export { };
class Node <T> {
private _key: number;
private _data: T;
private _leftChild: Node <T>;
private _rightChild: Node <T>;
constructor(key: number, data: T) {
this._key = key;
this._data = data;
}
get key(): number {
return this._key;
}
get data(): T {
return this._data;
}
get leftChild(): Node <T> {
return this._leftChild;
}
get rightChild(): Node <T> {
return this._rightChild;
}
set leftChild(child: Node <T>) {
this._leftChild = child;
}
set rightChild(child: Node <T>) {
this._rightChild = child;
}
}
class BinaryTree <H> {
private _root: Node<H>;
public addNode(key: number, data: H): void {
const newNode: Node <H> = new Node <H> (key, data);
if (this._root == null) {
this._root = newNode;
} else {
let focusNode: Node <H> = this._root;
let parent: Node <H>;
while (true) {
parent = focusNode;
if (key < focusNode.key) {
focusNode = focusNode.leftChild;
if (focusNode == null) {
parent.leftChild(newNode);
return;
}
}
}
}
}
}
javascript typescript oop data-structures binary-tree
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
1
I'm trying to implement binary search tree in Type Script using generic types. However I have an issue with adding child in node, because there is an error when parent.leftChild(newNode) - "Cannot invoke an expression whose type is lacks a call signature. Type Node has no compatible call signatures."
export { };
class Node <T> {
private _key: number;
private _data: T;
private _leftChild: Node <T>;
private _rightChild: Node <T>;
constructor(key: number, data: T) {
this._key = key;
this._data = data;
}
get key(): number {
return this._key;
}
get data(): T {
return this._data;
}
get leftChild(): Node <T> {
return this._leftChild;
}
get rightChild(): Node <T> {
return this._rightChild;
}
set leftChild(child: Node <T>) {
this._leftChild = child;
}
set rightChild(child: Node <T>) {
this._rightChild = child;
}
}
class BinaryTree <H> {
private _root: Node<H>;
public addNode(key: number, data: H): void {
const newNode: Node <H> = new Node <H> (key, data);
if (this._root == null) {
this._root = newNode;
} else {
let focusNode: Node <H> = this._root;
let parent: Node <H>;
while (true) {
parent = focusNode;
if (key < focusNode.key) {
focusNode = focusNode.leftChild;
if (focusNode == null) {
parent.leftChild(newNode);
return;
}
}
}
}
}
}
javascript typescript oop data-structures binary-tree
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
leftChildis a property setter not a function so tryparent.leftChild = newNode(typescriptlang.org/docs/handbook/classes.html#accessors)
– Peter Hull
Jan 18 at 14:15
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (markingdataandkeyas readonly)
– Peter Hull
Jan 18 at 15:45
add a comment |
1
1
1
I'm trying to implement binary search tree in Type Script using generic types. However I have an issue with adding child in node, because there is an error when parent.leftChild(newNode) - "Cannot invoke an expression whose type is lacks a call signature. Type Node has no compatible call signatures."
export { };
class Node <T> {
private _key: number;
private _data: T;
private _leftChild: Node <T>;
private _rightChild: Node <T>;
constructor(key: number, data: T) {
this._key = key;
this._data = data;
}
get key(): number {
return this._key;
}
get data(): T {
return this._data;
}
get leftChild(): Node <T> {
return this._leftChild;
}
get rightChild(): Node <T> {
return this._rightChild;
}
set leftChild(child: Node <T>) {
this._leftChild = child;
}
set rightChild(child: Node <T>) {
this._rightChild = child;
}
}
class BinaryTree <H> {
private _root: Node<H>;
public addNode(key: number, data: H): void {
const newNode: Node <H> = new Node <H> (key, data);
if (this._root == null) {
this._root = newNode;
} else {
let focusNode: Node <H> = this._root;
let parent: Node <H>;
while (true) {
parent = focusNode;
if (key < focusNode.key) {
focusNode = focusNode.leftChild;
if (focusNode == null) {
parent.leftChild(newNode);
return;
}
}
}
}
}
}
javascript typescript oop data-structures binary-tree
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm trying to implement binary search tree in Type Script using generic types. However I have an issue with adding child in node, because there is an error when parent.leftChild(newNode) - "Cannot invoke an expression whose type is lacks a call signature. Type Node has no compatible call signatures."
export { };
class Node <T> {
private _key: number;
private _data: T;
private _leftChild: Node <T>;
private _rightChild: Node <T>;
constructor(key: number, data: T) {
this._key = key;
this._data = data;
}
get key(): number {
return this._key;
}
get data(): T {
return this._data;
}
get leftChild(): Node <T> {
return this._leftChild;
}
get rightChild(): Node <T> {
return this._rightChild;
}
set leftChild(child: Node <T>) {
this._leftChild = child;
}
set rightChild(child: Node <T>) {
this._rightChild = child;
}
}
class BinaryTree <H> {
private _root: Node<H>;
public addNode(key: number, data: H): void {
const newNode: Node <H> = new Node <H> (key, data);
if (this._root == null) {
this._root = newNode;
} else {
let focusNode: Node <H> = this._root;
let parent: Node <H>;
while (true) {
parent = focusNode;
if (key < focusNode.key) {
focusNode = focusNode.leftChild;
if (focusNode == null) {
parent.leftChild(newNode);
return;
}
}
}
}
}
}
javascript typescript oop data-structures binary-tree
javascript typescript oop data-structures binary-tree
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
asked Jan 18 at 14:02
Mr. VazovskyMr. Vazovsky
61
61
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mr. Vazovsky is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
leftChildis a property setter not a function so tryparent.leftChild = newNode(typescriptlang.org/docs/handbook/classes.html#accessors)
– Peter Hull
Jan 18 at 14:15
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (markingdataandkeyas readonly)
– Peter Hull
Jan 18 at 15:45
add a comment |
leftChildis a property setter not a function so tryparent.leftChild = newNode(typescriptlang.org/docs/handbook/classes.html#accessors)
– Peter Hull
Jan 18 at 14:15
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (markingdataandkeyas readonly)
– Peter Hull
Jan 18 at 15:45
leftChild is a property setter not a function so try parent.leftChild = newNode (typescriptlang.org/docs/handbook/classes.html#accessors)– Peter Hull
Jan 18 at 14:15
leftChild is a property setter not a function so try parent.leftChild = newNode (typescriptlang.org/docs/handbook/classes.html#accessors)– Peter Hull
Jan 18 at 14:15
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (marking
data and key as readonly)– Peter Hull
Jan 18 at 15:45
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (marking
data and key as readonly)– Peter Hull
Jan 18 at 15:45
add a comment |
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leftChildis a property setter not a function so tryparent.leftChild = newNode(typescriptlang.org/docs/handbook/classes.html#accessors)– Peter Hull
Jan 18 at 14:15
@peter-hull Thanks man! It works! I've tried to fix it for over 24 last hours)) Why TS has so weird syntax????)
– Mr. Vazovsky
Jan 18 at 14:28
Glad it works. As an aside, since your property accessors don't have any computation in them, you can just expose the bare properties (marking
dataandkeyas readonly)– Peter Hull
Jan 18 at 15:45