How to convert compact Json to pretty print codename one

I want to know how to convert a string of compact Json to pretty print so that I can parse it. I have searched for this question in stack overflow but it doesn't seem like anyone has asked it for codename one.
Right now I have a string of compact Json but it can not be parsed. This is the code:

String JsonData = "{"document":{ "type":"PLAIN_TEXT", "content":"Ask not what your country can do for you, ask what you can do for your country." },"encodingType":"UTF8"}";

            JsonResponse = Rest.

                post("https://language.googleapis.com/v1/documents:analyzeSyntax?key=[API KEY").

                    jsonContent().

                    body(JsonData).

                    getAsJsonMap();

            String JsonString = (JsonResponse.getResponseData()).toString();

            JSONParser parser = new JSONParser();

            Map<String, Object> results = null;

            try {

                results = parser.parseJSON(new StringReader(JsonString));

            } catch (IOException e) {

                e.printStackTrace();

                System.out.println("fail");

            }

            System.out.println("results   "+results);

But when I run this code I get a bunch of these responses:

[EDT] 0:0:3,269 - Expected null for key value while parsing JSON token at row: 1 column: 5 buffer: e

and

java.lang.NumberFormatException: For input string: "ee0"

How should I convert my string of compact Json (JsonString) to pretty print so that I can parse it? Alternatively, is there a way to directly parse the response (JsonResponse)?
Thank You

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

could you post your full code? this obviously doesn't compile.

– cen0r
Jan 18 at 23:47

My program is pretty long but this is a free standing part: nothing else in the program affects this request.

– Max Litvak
Jan 19 at 1:56

add a comment |

String JsonData = "{"document":{ "type":"PLAIN_TEXT", "content":"Ask not what your country can do for you, ask what you can do for your country." },"encodingType":"UTF8"}";

            JsonResponse = Rest.

                post("https://language.googleapis.com/v1/documents:analyzeSyntax?key=[API KEY").

                    jsonContent().

                    body(JsonData).

                    getAsJsonMap();

            String JsonString = (JsonResponse.getResponseData()).toString();

            JSONParser parser = new JSONParser();

            Map<String, Object> results = null;

            try {

                results = parser.parseJSON(new StringReader(JsonString));

            } catch (IOException e) {

                e.printStackTrace();

                System.out.println("fail");

            }

            System.out.println("results   "+results);

But when I run this code I get a bunch of these responses:

[EDT] 0:0:3,269 - Expected null for key value while parsing JSON token at row: 1 column: 5 buffer: e

and

java.lang.NumberFormatException: For input string: "ee0"

How should I convert my string of compact Json (JsonString) to pretty print so that I can parse it? Alternatively, is there a way to directly parse the response (JsonResponse)?
Thank You

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

could you post your full code? this obviously doesn't compile.

– cen0r
Jan 18 at 23:47

My program is pretty long but this is a free standing part: nothing else in the program affects this request.

– Max Litvak
Jan 19 at 1:56

add a comment |

String JsonData = "{"document":{ "type":"PLAIN_TEXT", "content":"Ask not what your country can do for you, ask what you can do for your country." },"encodingType":"UTF8"}";

            JsonResponse = Rest.

                post("https://language.googleapis.com/v1/documents:analyzeSyntax?key=[API KEY").

                    jsonContent().

                    body(JsonData).

                    getAsJsonMap();

            String JsonString = (JsonResponse.getResponseData()).toString();

            JSONParser parser = new JSONParser();

            Map<String, Object> results = null;

            try {

                results = parser.parseJSON(new StringReader(JsonString));

            } catch (IOException e) {

                e.printStackTrace();

                System.out.println("fail");

            }

            System.out.println("results   "+results);

But when I run this code I get a bunch of these responses:

[EDT] 0:0:3,269 - Expected null for key value while parsing JSON token at row: 1 column: 5 buffer: e

and

java.lang.NumberFormatException: For input string: "ee0"

How should I convert my string of compact Json (JsonString) to pretty print so that I can parse it? Alternatively, is there a way to directly parse the response (JsonResponse)?
Thank You

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

String JsonData = "{"document":{ "type":"PLAIN_TEXT", "content":"Ask not what your country can do for you, ask what you can do for your country." },"encodingType":"UTF8"}";

            JsonResponse = Rest.

                post("https://language.googleapis.com/v1/documents:analyzeSyntax?key=[API KEY").

                    jsonContent().

                    body(JsonData).

                    getAsJsonMap();

            String JsonString = (JsonResponse.getResponseData()).toString();

            JSONParser parser = new JSONParser();

            Map<String, Object> results = null;

            try {

                results = parser.parseJSON(new StringReader(JsonString));

            } catch (IOException e) {

                e.printStackTrace();

                System.out.println("fail");

            }

            System.out.println("results   "+results);

But when I run this code I get a bunch of these responses:

[EDT] 0:0:3,269 - Expected null for key value while parsing JSON token at row: 1 column: 5 buffer: e

and

java.lang.NumberFormatException: For input string: "ee0"

How should I convert my string of compact Json (JsonString) to pretty print so that I can parse it? Alternatively, is there a way to directly parse the response (JsonResponse)?
Thank You

json codenameone pretty-print

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

edited Jan 18 at 23:44

asked Jan 18 at 23:29

Max Litvak

183

asked Jan 18 at 23:29

Max Litvak

183

asked Jan 18 at 23:29

Max Litvak

183

could you post your full code? this obviously doesn't compile.

– cen0r
Jan 18 at 23:47

My program is pretty long but this is a free standing part: nothing else in the program affects this request.

– Max Litvak
Jan 19 at 1:56

add a comment |

could you post your full code? this obviously doesn't compile.

– cen0r
Jan 18 at 23:47

My program is pretty long but this is a free standing part: nothing else in the program affects this request.

– Max Litvak
Jan 19 at 1:56

could you post your full code? this obviously doesn't compile.

– cen0r
Jan 18 at 23:47

My program is pretty long but this is a free standing part: nothing else in the program affects this request.

– Max Litvak
Jan 19 at 1:56

add a comment |

1 Answer
1

active

oldest

votes

You are printing out a map not a JSON string as the JSON data is already parsed. If you just want to look at the network protocol for debugging the best way to do that is open the Network Monitor in the simulator where you will see all HTTP requests and can copy out the response body JSON.

However you can still convert a Map back to JSON using:

Log.p("results   " + JSONParser.mapToJson(results));

Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.

answered Jan 19 at 5:41

Shai Almog

40.3k52555

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

However you can still convert a Map back to JSON using:

Log.p("results   " + JSONParser.mapToJson(results));

Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.

answered Jan 19 at 5:41

Shai Almog

40.3k52555

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

add a comment |

However you can still convert a Map back to JSON using:

Log.p("results   " + JSONParser.mapToJson(results));

Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.

answered Jan 19 at 5:41

Shai Almog

40.3k52555

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

add a comment |

However you can still convert a Map back to JSON using:

Log.p("results   " + JSONParser.mapToJson(results));

Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.

answered Jan 19 at 5:41

Shai Almog

40.3k52555

However you can still convert a Map back to JSON using:

Log.p("results   " + JSONParser.mapToJson(results));

Notice you should use Log.p() and Log.e() to log strings/exceptions as that would work better on the devices.

answered Jan 19 at 5:41

Shai Almog

40.3k52555

answered Jan 19 at 5:41

Shai Almog

40.3k52555

answered Jan 19 at 5:41

Shai Almog

40.3k52555

answered Jan 19 at 5:41

Shai Almog

40.3k52555

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

add a comment |

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

Thank you. That line of code was helpful. I think that I was asking the wrong questions though. I wanted to put the response into a Map<String, Object> and I did not realize that you could just do Response = Map<String, Object>.

– Max Litvak
Jan 19 at 13:19

add a comment |

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