How to return each path and its hash from multidimensional array?












0















I'm trying to return each path of a multidimensional array along with its hash value. I've used this solution:



function newMethod($tree) {
$hash = "";
$final = array();
foreach ($tree as $key => &$mixed) {
if (is_array($mixed) || is_object($mixed)) {
$results = newMethod($mixed);
foreach ($results as $k => &$v) {
$hash = md5($key . $v);
if(is_array($mixed)) {
$final[$hash] = array($key => $v);
}
elseif(is_object($mixed)) {
$final[$hash] = array($key => (object)$v);
}
}
unset($results);
} else {
$hash = md5($key. $mixed);
$final[$hash] = array($key => $mixed);
}
}
return $final;
}


Using this function provides the hash value for each section of the path separately and doesn't connect them together. How can I change this solution to get an output like this:



Array
(
[0] => Array
(
[Hash of first path] => Array
(
[a] => b
)
)
[1] => Array
(
[Hash of second path] => Array
(
[c] => stdClass Object
(
[d] => Array
(
[1] => 11
)
)

)

)
)
...


The simple tree and a part of output are as follows:



$new = [
'a' => 'b',
'c' => (object)[
'd' => [1 => 11, 2 => 12],
'f' => 'Hello',
],
];
//output
[0] => Array
(
[187ef4436122d1cc2f40dc2b92f0eba0] => Array
(
[a] => b
)

)

[1] => Array
(
[595448f796fd1d2d5f192949d79ba9df] => Array
(
[c] => stdClass Object
(
[f801394efb8c6ca75f1ab6a639556520] => Array
(
[d] => Array
(
[698d51a19d8a121ce581499d7b701668] => Array
(
[1] => 11
)

)

)

)

)

)
...









share|improve this question

























  • Can you post the tree?

    – Ussaid Iqbal
    Jan 19 at 9:41











  • Can you add the data in your desire output? should the "first path" be string as "a->b"?

    – dWinder
    Jan 22 at 13:46


















0















I'm trying to return each path of a multidimensional array along with its hash value. I've used this solution:



function newMethod($tree) {
$hash = "";
$final = array();
foreach ($tree as $key => &$mixed) {
if (is_array($mixed) || is_object($mixed)) {
$results = newMethod($mixed);
foreach ($results as $k => &$v) {
$hash = md5($key . $v);
if(is_array($mixed)) {
$final[$hash] = array($key => $v);
}
elseif(is_object($mixed)) {
$final[$hash] = array($key => (object)$v);
}
}
unset($results);
} else {
$hash = md5($key. $mixed);
$final[$hash] = array($key => $mixed);
}
}
return $final;
}


Using this function provides the hash value for each section of the path separately and doesn't connect them together. How can I change this solution to get an output like this:



Array
(
[0] => Array
(
[Hash of first path] => Array
(
[a] => b
)
)
[1] => Array
(
[Hash of second path] => Array
(
[c] => stdClass Object
(
[d] => Array
(
[1] => 11
)
)

)

)
)
...


The simple tree and a part of output are as follows:



$new = [
'a' => 'b',
'c' => (object)[
'd' => [1 => 11, 2 => 12],
'f' => 'Hello',
],
];
//output
[0] => Array
(
[187ef4436122d1cc2f40dc2b92f0eba0] => Array
(
[a] => b
)

)

[1] => Array
(
[595448f796fd1d2d5f192949d79ba9df] => Array
(
[c] => stdClass Object
(
[f801394efb8c6ca75f1ab6a639556520] => Array
(
[d] => Array
(
[698d51a19d8a121ce581499d7b701668] => Array
(
[1] => 11
)

)

)

)

)

)
...









share|improve this question

























  • Can you post the tree?

    – Ussaid Iqbal
    Jan 19 at 9:41











  • Can you add the data in your desire output? should the "first path" be string as "a->b"?

    – dWinder
    Jan 22 at 13:46
















0












0








0








I'm trying to return each path of a multidimensional array along with its hash value. I've used this solution:



function newMethod($tree) {
$hash = "";
$final = array();
foreach ($tree as $key => &$mixed) {
if (is_array($mixed) || is_object($mixed)) {
$results = newMethod($mixed);
foreach ($results as $k => &$v) {
$hash = md5($key . $v);
if(is_array($mixed)) {
$final[$hash] = array($key => $v);
}
elseif(is_object($mixed)) {
$final[$hash] = array($key => (object)$v);
}
}
unset($results);
} else {
$hash = md5($key. $mixed);
$final[$hash] = array($key => $mixed);
}
}
return $final;
}


Using this function provides the hash value for each section of the path separately and doesn't connect them together. How can I change this solution to get an output like this:



Array
(
[0] => Array
(
[Hash of first path] => Array
(
[a] => b
)
)
[1] => Array
(
[Hash of second path] => Array
(
[c] => stdClass Object
(
[d] => Array
(
[1] => 11
)
)

)

)
)
...


The simple tree and a part of output are as follows:



$new = [
'a' => 'b',
'c' => (object)[
'd' => [1 => 11, 2 => 12],
'f' => 'Hello',
],
];
//output
[0] => Array
(
[187ef4436122d1cc2f40dc2b92f0eba0] => Array
(
[a] => b
)

)

[1] => Array
(
[595448f796fd1d2d5f192949d79ba9df] => Array
(
[c] => stdClass Object
(
[f801394efb8c6ca75f1ab6a639556520] => Array
(
[d] => Array
(
[698d51a19d8a121ce581499d7b701668] => Array
(
[1] => 11
)

)

)

)

)

)
...









share|improve this question
















I'm trying to return each path of a multidimensional array along with its hash value. I've used this solution:



function newMethod($tree) {
$hash = "";
$final = array();
foreach ($tree as $key => &$mixed) {
if (is_array($mixed) || is_object($mixed)) {
$results = newMethod($mixed);
foreach ($results as $k => &$v) {
$hash = md5($key . $v);
if(is_array($mixed)) {
$final[$hash] = array($key => $v);
}
elseif(is_object($mixed)) {
$final[$hash] = array($key => (object)$v);
}
}
unset($results);
} else {
$hash = md5($key. $mixed);
$final[$hash] = array($key => $mixed);
}
}
return $final;
}


Using this function provides the hash value for each section of the path separately and doesn't connect them together. How can I change this solution to get an output like this:



Array
(
[0] => Array
(
[Hash of first path] => Array
(
[a] => b
)
)
[1] => Array
(
[Hash of second path] => Array
(
[c] => stdClass Object
(
[d] => Array
(
[1] => 11
)
)

)

)
)
...


The simple tree and a part of output are as follows:



$new = [
'a' => 'b',
'c' => (object)[
'd' => [1 => 11, 2 => 12],
'f' => 'Hello',
],
];
//output
[0] => Array
(
[187ef4436122d1cc2f40dc2b92f0eba0] => Array
(
[a] => b
)

)

[1] => Array
(
[595448f796fd1d2d5f192949d79ba9df] => Array
(
[c] => stdClass Object
(
[f801394efb8c6ca75f1ab6a639556520] => Array
(
[d] => Array
(
[698d51a19d8a121ce581499d7b701668] => Array
(
[1] => 11
)

)

)

)

)

)
...






php arrays multidimensional-array hash tree






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 22 at 14:01







F.Ndr

















asked Jan 19 at 9:37









F.NdrF.Ndr

275




275













  • Can you post the tree?

    – Ussaid Iqbal
    Jan 19 at 9:41











  • Can you add the data in your desire output? should the "first path" be string as "a->b"?

    – dWinder
    Jan 22 at 13:46





















  • Can you post the tree?

    – Ussaid Iqbal
    Jan 19 at 9:41











  • Can you add the data in your desire output? should the "first path" be string as "a->b"?

    – dWinder
    Jan 22 at 13:46



















Can you post the tree?

– Ussaid Iqbal
Jan 19 at 9:41





Can you post the tree?

– Ussaid Iqbal
Jan 19 at 9:41













Can you add the data in your desire output? should the "first path" be string as "a->b"?

– dWinder
Jan 22 at 13:46







Can you add the data in your desire output? should the "first path" be string as "a->b"?

– dWinder
Jan 22 at 13:46














0






active

oldest

votes











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54265766%2fhow-to-return-each-path-and-its-hash-from-multidimensional-array%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54265766%2fhow-to-return-each-path-and-its-hash-from-multidimensional-array%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Liquibase includeAll doesn't find base path

How to use setInterval in EJS file?

Petrus Granier-Deferre