Brtdku

i'm relatively new to python/programming and even more of a noob in json.

I am making a dictionary app for a side projects that I have, it works fine, I can search for words and get their definition, but I want to make it perfect and I want the results to be readable for the final user (I know about indenting but I don't want the brackets and all the json formatting to appear in the results)

So this is the json i'm pulling the data from:

{

 "Bonjour": {

  "English Word": "Hello",

  "Type of word": "whatever",

  "Defintion": "Means good day",

  "Use case example": "Bonjour igo",

  "Additional information": "BRO"

 }

}

and this is the code i'm using to get the values (it doesn't work), the "search" variable is = to "Bonjour" in this case (it's a user input)

currentword = json.load(data) #part of the "with open..."





for definition in currentword[search]['English Word', 'Definition', 'Use case example']:

    print(definition)

the error I get is the following:

KeyError: ('English Word', 'Definition', 'Use case example')

Now i'm unsure if "Bonjour" is the key or "English Word", etc... are the keys, if not, what is "Bonjour"

Anyways, I want it to print the values of "English Word" and preferably as "English Word - VALUE/DEFINITION"

Thanks for any help

From your problem, looks like you want to extract only some of the key-value pairs from your existing dictionary.

Try like below:

data = {

 "Bonjour": {

  "English Word": "Hello",

  "Type of word": "whatever",

  "Definition": "Means good day",

  "Use case example": "Bonjour igo",

  "Additional information": "BRO"

  }

  }



currentword = data

search = "Bonjour"



result = dict((k, currentword[search][k]) for k in ['English Word', 'Definition', 'Use case example'])



for k,v in result.items():

    print k + ":" + v

Result:

Definition:Means good day 

English Word:Hello 

Use case example:Bonjour igo

JSON format is simply a nice way to pair keys and values.
Keys are the names we give to Values, so it will be easy to access them.

If we took your JSON, and split it by keys and values, this is what we would get:

Keys: "Bonjour", "English Word", "Type of word", "Defintion", "Use case example", "Additional information".

Showing all values is a little complex, so I'll explain:

The value of "Bonjour" is this:

{

  "English Word": "Hello",

  "Type of word": "whatever",

  "Defintion": "Means good day",

  "Use case example": "Bonjour igo",

  "Additional information": "BRO"

}

And all other value are described in the value of "Bonjour".

The value of "English Word" is "Hello" and so on.

When you write a line like so: currentword[search]['English Word', 'Definition', 'Use case example'], you are telling Python to look for a key named ('English Word', 'Definition', 'Use case example'), and obviously it does not exist.

What you should do is as follows:

for definition in currentword[search]:

    eng_word = definition['English Word']

    print('English Word - {}'.format(eng_word))

please note that definition contain all other fields as well, so you can choose whichever one you like.

This line:

currentword[search]['English Word', 'Definition', 'Use case example']

Calls 'English Word', 'Definition', 'Use case example' as a tuple key from the inner dict, which doesn't exist in your dictionary, which is why a KeyError is raised.

If you want just the english word, use this instead:

currentword[search]["English Word"]

Assuming search is "Bonjour".

It also looks like you are also trying to filter out specific keys from the inner dict separately. If this is the case, you can do this:

d = {

 "Bonjour": {

  "English Word": "Hello",

  "Type of word": "whatever",

  "Defintion": "Means good day",

  "Use case example": "Bonjour igo",

  "Additional information": "BRO"

 }

}



inner_dict = d['Bonjour']



keys = ["English Word", "Use case example", "Defintion"]



print({k: inner_dict[k] for k in keys})

# {'English Word': 'Hello', 'Use case example': 'Bonjour igo', 'Defintion': 'Means good day'}