Using regular expression to divide two words and capture the first word












0















following part-of-speech tagged sentence: All/DT animals/NNS are/VBP equal/JJ ,/,
but/CC some/DT animals/NNS are/VBP more/RBR equal/JJ than/IN others/NNS ./.



How to write a regular expression that matches only the words of each word/pos-tag in the sentence.



text="""All/DT animals/NNS are/VBP equal/JJ ,/, but/CC some/DT animals/NNS 
are/VBP more/RBR equal/JJ than/IN others/NNS ./."""
tokens=nltk.word_tokenize(text)
pattern="([A-Za-z]+)|[A-Za-z]"
print("Upper case words:")
for tok in tokens:
if re.search(pattern, tok) is not None:
print("'{}'".format(tok))









share|improve this question























  • What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

    – Pushpesh Kumar Rajwanshi
    Jan 20 at 7:11






  • 2





    post the expected result

    – RomanPerekhrest
    Jan 20 at 7:15











  • You show some code. What is the problem with it?

    – Mad Physicist
    Jan 20 at 7:20











  • Is there any result you are expecting? Please post it.

    – Austin
    Jan 20 at 7:22











  • I want my regex to match only words (All, animals , are , equal , etc)

    – Shideh Hm
    Jan 20 at 7:30
















0















following part-of-speech tagged sentence: All/DT animals/NNS are/VBP equal/JJ ,/,
but/CC some/DT animals/NNS are/VBP more/RBR equal/JJ than/IN others/NNS ./.



How to write a regular expression that matches only the words of each word/pos-tag in the sentence.



text="""All/DT animals/NNS are/VBP equal/JJ ,/, but/CC some/DT animals/NNS 
are/VBP more/RBR equal/JJ than/IN others/NNS ./."""
tokens=nltk.word_tokenize(text)
pattern="([A-Za-z]+)|[A-Za-z]"
print("Upper case words:")
for tok in tokens:
if re.search(pattern, tok) is not None:
print("'{}'".format(tok))









share|improve this question























  • What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

    – Pushpesh Kumar Rajwanshi
    Jan 20 at 7:11






  • 2





    post the expected result

    – RomanPerekhrest
    Jan 20 at 7:15











  • You show some code. What is the problem with it?

    – Mad Physicist
    Jan 20 at 7:20











  • Is there any result you are expecting? Please post it.

    – Austin
    Jan 20 at 7:22











  • I want my regex to match only words (All, animals , are , equal , etc)

    – Shideh Hm
    Jan 20 at 7:30














0












0








0








following part-of-speech tagged sentence: All/DT animals/NNS are/VBP equal/JJ ,/,
but/CC some/DT animals/NNS are/VBP more/RBR equal/JJ than/IN others/NNS ./.



How to write a regular expression that matches only the words of each word/pos-tag in the sentence.



text="""All/DT animals/NNS are/VBP equal/JJ ,/, but/CC some/DT animals/NNS 
are/VBP more/RBR equal/JJ than/IN others/NNS ./."""
tokens=nltk.word_tokenize(text)
pattern="([A-Za-z]+)|[A-Za-z]"
print("Upper case words:")
for tok in tokens:
if re.search(pattern, tok) is not None:
print("'{}'".format(tok))









share|improve this question














following part-of-speech tagged sentence: All/DT animals/NNS are/VBP equal/JJ ,/,
but/CC some/DT animals/NNS are/VBP more/RBR equal/JJ than/IN others/NNS ./.



How to write a regular expression that matches only the words of each word/pos-tag in the sentence.



text="""All/DT animals/NNS are/VBP equal/JJ ,/, but/CC some/DT animals/NNS 
are/VBP more/RBR equal/JJ than/IN others/NNS ./."""
tokens=nltk.word_tokenize(text)
pattern="([A-Za-z]+)|[A-Za-z]"
print("Upper case words:")
for tok in tokens:
if re.search(pattern, tok) is not None:
print("'{}'".format(tok))






python regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 20 at 7:03









Shideh HmShideh Hm

193




193













  • What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

    – Pushpesh Kumar Rajwanshi
    Jan 20 at 7:11






  • 2





    post the expected result

    – RomanPerekhrest
    Jan 20 at 7:15











  • You show some code. What is the problem with it?

    – Mad Physicist
    Jan 20 at 7:20











  • Is there any result you are expecting? Please post it.

    – Austin
    Jan 20 at 7:22











  • I want my regex to match only words (All, animals , are , equal , etc)

    – Shideh Hm
    Jan 20 at 7:30



















  • What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

    – Pushpesh Kumar Rajwanshi
    Jan 20 at 7:11






  • 2





    post the expected result

    – RomanPerekhrest
    Jan 20 at 7:15











  • You show some code. What is the problem with it?

    – Mad Physicist
    Jan 20 at 7:20











  • Is there any result you are expecting? Please post it.

    – Austin
    Jan 20 at 7:22











  • I want my regex to match only words (All, animals , are , equal , etc)

    – Shideh Hm
    Jan 20 at 7:30

















What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

– Pushpesh Kumar Rajwanshi
Jan 20 at 7:11





What do you want your regex to match? capital letter text preceded by /? like DT NNS VBP etc?

– Pushpesh Kumar Rajwanshi
Jan 20 at 7:11




2




2





post the expected result

– RomanPerekhrest
Jan 20 at 7:15





post the expected result

– RomanPerekhrest
Jan 20 at 7:15













You show some code. What is the problem with it?

– Mad Physicist
Jan 20 at 7:20





You show some code. What is the problem with it?

– Mad Physicist
Jan 20 at 7:20













Is there any result you are expecting? Please post it.

– Austin
Jan 20 at 7:22





Is there any result you are expecting? Please post it.

– Austin
Jan 20 at 7:22













I want my regex to match only words (All, animals , are , equal , etc)

– Shideh Hm
Jan 20 at 7:30





I want my regex to match only words (All, animals , are , equal , etc)

– Shideh Hm
Jan 20 at 7:30












2 Answers
2






active

oldest

votes


















2














Using re.findall



import re
print (re.findall(r'([a-zA-Z]+)/[a-zA-Z]+',text))
#['All', 'animals', 'are', 'equal', 'but', 'some', 'animals', 'are', 'more', 'equal', 'than', 'others']





share|improve this answer
























  • Thanks. but how to match the "." at the end of the sentence?

    – Shideh Hm
    Jan 20 at 8:59



















0














You can use the following regex:



(S+)/S+s?


Explaination:



(S+) is a capturing group which matches any non-whitespace character
/ matches the character /
S+ matches non-whitespace character, but not captured this time
s? optional space at the end



Here's a link to test the regex and get explanation



As @Transhuman suggested use re.findall to get all the matches:



import re
print (re.findall(r'(S+)/S+s?',text))


You can test the python code here:






share|improve this answer

























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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    Using re.findall



    import re
    print (re.findall(r'([a-zA-Z]+)/[a-zA-Z]+',text))
    #['All', 'animals', 'are', 'equal', 'but', 'some', 'animals', 'are', 'more', 'equal', 'than', 'others']





    share|improve this answer
























    • Thanks. but how to match the "." at the end of the sentence?

      – Shideh Hm
      Jan 20 at 8:59
















    2














    Using re.findall



    import re
    print (re.findall(r'([a-zA-Z]+)/[a-zA-Z]+',text))
    #['All', 'animals', 'are', 'equal', 'but', 'some', 'animals', 'are', 'more', 'equal', 'than', 'others']





    share|improve this answer
























    • Thanks. but how to match the "." at the end of the sentence?

      – Shideh Hm
      Jan 20 at 8:59














    2












    2








    2







    Using re.findall



    import re
    print (re.findall(r'([a-zA-Z]+)/[a-zA-Z]+',text))
    #['All', 'animals', 'are', 'equal', 'but', 'some', 'animals', 'are', 'more', 'equal', 'than', 'others']





    share|improve this answer













    Using re.findall



    import re
    print (re.findall(r'([a-zA-Z]+)/[a-zA-Z]+',text))
    #['All', 'animals', 'are', 'equal', 'but', 'some', 'animals', 'are', 'more', 'equal', 'than', 'others']






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 20 at 7:33









    TranshumanTranshuman

    2,7761411




    2,7761411













    • Thanks. but how to match the "." at the end of the sentence?

      – Shideh Hm
      Jan 20 at 8:59



















    • Thanks. but how to match the "." at the end of the sentence?

      – Shideh Hm
      Jan 20 at 8:59

















    Thanks. but how to match the "." at the end of the sentence?

    – Shideh Hm
    Jan 20 at 8:59





    Thanks. but how to match the "." at the end of the sentence?

    – Shideh Hm
    Jan 20 at 8:59













    0














    You can use the following regex:



    (S+)/S+s?


    Explaination:



    (S+) is a capturing group which matches any non-whitespace character
    / matches the character /
    S+ matches non-whitespace character, but not captured this time
    s? optional space at the end



    Here's a link to test the regex and get explanation



    As @Transhuman suggested use re.findall to get all the matches:



    import re
    print (re.findall(r'(S+)/S+s?',text))


    You can test the python code here:






    share|improve this answer






























      0














      You can use the following regex:



      (S+)/S+s?


      Explaination:



      (S+) is a capturing group which matches any non-whitespace character
      / matches the character /
      S+ matches non-whitespace character, but not captured this time
      s? optional space at the end



      Here's a link to test the regex and get explanation



      As @Transhuman suggested use re.findall to get all the matches:



      import re
      print (re.findall(r'(S+)/S+s?',text))


      You can test the python code here:






      share|improve this answer




























        0












        0








        0







        You can use the following regex:



        (S+)/S+s?


        Explaination:



        (S+) is a capturing group which matches any non-whitespace character
        / matches the character /
        S+ matches non-whitespace character, but not captured this time
        s? optional space at the end



        Here's a link to test the regex and get explanation



        As @Transhuman suggested use re.findall to get all the matches:



        import re
        print (re.findall(r'(S+)/S+s?',text))


        You can test the python code here:






        share|improve this answer















        You can use the following regex:



        (S+)/S+s?


        Explaination:



        (S+) is a capturing group which matches any non-whitespace character
        / matches the character /
        S+ matches non-whitespace character, but not captured this time
        s? optional space at the end



        Here's a link to test the regex and get explanation



        As @Transhuman suggested use re.findall to get all the matches:



        import re
        print (re.findall(r'(S+)/S+s?',text))


        You can test the python code here:







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Jan 20 at 10:33

























        answered Jan 20 at 10:17









        adigaadiga

        8,50362241




        8,50362241






























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