How to concatenate a php variable in an echo statement with a javascript onClick event?
I am developing an application where each user has a uid and that uid is a folder. I have changed the name of the current directory to the uid and this displays the proper files on a dropdown of the files in the folder that is on the page but then the location still goes to the parent folder and not the the uid folder. How do I concatenate the uid variable with the location so it is going to the right folder? Here is what I have so far
<?php
chdir("$uid");
echo "<select name='menu'>";
$files = array_filter(scandir($dir), function($item) {
return $item[0] !== '.';
});
foreach (glob("*.php") as $file){
if ($file != 'new.php' && $file !='config.php'){
echo "<option value='$file'>".basename($file,".php"). "</option>";
}
}
echo "</select>";
echo "<input type='button' onClick='location=this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
echo "</form>";
?>
I have tried doing this:
echo "<input type='button' onClick='location='$uid/'.this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
But then I run into syntax errors. Is there a way I can concatenate the uid with the location file name?
javascript php html
asked Jan 20 at 0:18
J DoeJ Doe
124
add a comment |
I am developing an application where each user has a uid and that uid is a folder. I have changed the name of the current directory to the uid and this displays the proper files on a dropdown of the files in the folder that is on the page but then the location still goes to the parent folder and not the the uid folder. How do I concatenate the uid variable with the location so it is going to the right folder? Here is what I have so far
<?php
chdir("$uid");
echo "<select name='menu'>";
$files = array_filter(scandir($dir), function($item) {
return $item[0] !== '.';
});
foreach (glob("*.php") as $file){
if ($file != 'new.php' && $file !='config.php'){
echo "<option value='$file'>".basename($file,".php"). "</option>";
}
}
echo "</select>";
echo "<input type='button' onClick='location=this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
echo "</form>";
?>
I have tried doing this:
echo "<input type='button' onClick='location='$uid/'.this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
But then I run into syntax errors. Is there a way I can concatenate the uid with the location file name?
javascript php html
asked Jan 20 at 0:18
J DoeJ Doe
124
2
HTML attributes, e.g.onClick, must have their values enclosed within double quotes, e.g.onClick="your_code_goes_here". YouronClickis likely failing because you never added that in. Be sure to enclose theonClickJavaScript in double quotes, remembering to escape those quotes i.e. doonClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.
– B. Fleming
Jan 20 at 0:38
add a comment |
I am developing an application where each user has a uid and that uid is a folder. I have changed the name of the current directory to the uid and this displays the proper files on a dropdown of the files in the folder that is on the page but then the location still goes to the parent folder and not the the uid folder. How do I concatenate the uid variable with the location so it is going to the right folder? Here is what I have so far
<?php
chdir("$uid");
echo "<select name='menu'>";
$files = array_filter(scandir($dir), function($item) {
return $item[0] !== '.';
});
foreach (glob("*.php") as $file){
if ($file != 'new.php' && $file !='config.php'){
echo "<option value='$file'>".basename($file,".php"). "</option>";
}
}
echo "</select>";
echo "<input type='button' onClick='location=this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
echo "</form>";
?>
I have tried doing this:
echo "<input type='button' onClick='location='$uid/'.this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
But then I run into syntax errors. Is there a way I can concatenate the uid with the location file name?
javascript php html
asked Jan 20 at 0:18
J DoeJ Doe
124
I am developing an application where each user has a uid and that uid is a folder. I have changed the name of the current directory to the uid and this displays the proper files on a dropdown of the files in the folder that is on the page but then the location still goes to the parent folder and not the the uid folder. How do I concatenate the uid variable with the location so it is going to the right folder? Here is what I have so far
<?php
chdir("$uid");
echo "<select name='menu'>";
$files = array_filter(scandir($dir), function($item) {
return $item[0] !== '.';
});
foreach (glob("*.php") as $file){
if ($file != 'new.php' && $file !='config.php'){
echo "<option value='$file'>".basename($file,".php"). "</option>";
}
}
echo "</select>";
echo "<input type='button' onClick='location=this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
echo "</form>";
?>
I have tried doing this:
echo "<input type='button' onClick='location='$uid/'.this.form.menu.options[this.form.menu.selectedIndex].value;'
value='GO'>";
But then I run into syntax errors. Is there a way I can concatenate the uid with the location file name?
javascript php html
javascript php html
asked Jan 20 at 0:18
J DoeJ Doe
124
asked Jan 20 at 0:18
J DoeJ Doe
124
asked Jan 20 at 0:18
J DoeJ Doe
124
asked Jan 20 at 0:18
J DoeJ Doe
124
asked Jan 20 at 0:18
J DoeJ Doe
124
124
2
HTML attributes, e.g.onClick, must have their values enclosed within double quotes, e.g.onClick="your_code_goes_here". YouronClickis likely failing because you never added that in. Be sure to enclose theonClickJavaScript in double quotes, remembering to escape those quotes i.e. doonClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.
– B. Fleming
Jan 20 at 0:38
add a comment |
2
HTML attributes, e.g.onClick, must have their values enclosed within double quotes, e.g.onClick="your_code_goes_here". YouronClickis likely failing because you never added that in. Be sure to enclose theonClickJavaScript in double quotes, remembering to escape those quotes i.e. doonClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.
– B. Fleming
Jan 20 at 0:38
2
2
HTML attributes, e.g.
onClick, must have their values enclosed within double quotes, e.g. onClick="your_code_goes_here". Your onClick is likely failing because you never added that in. Be sure to enclose the onClick JavaScript in double quotes, remembering to escape those quotes i.e. do onClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.– B. Fleming
Jan 20 at 0:38
HTML attributes, e.g.
onClick, must have their values enclosed within double quotes, e.g. onClick="your_code_goes_here". Your onClick is likely failing because you never added that in. Be sure to enclose the onClick JavaScript in double quotes, remembering to escape those quotes i.e. do onClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.– B. Fleming
Jan 20 at 0:38
add a comment |
1 Answer
1
active
oldest
votes
You can concatenate string in js with "+" operator, while in php you should use "."
So you can try this: (i didn't test it)
echo '<input type="button" onClick="location=''.$uid.'/'+this.form.menu.options[this.form.menu.selectedIndex].value;" value="GO">';
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can concatenate string in js with "+" operator, while in php you should use "."
So you can try this: (i didn't test it)
echo '<input type="button" onClick="location=''.$uid.'/'+this.form.menu.options[this.form.menu.selectedIndex].value;" value="GO">';
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
add a comment |
You can concatenate string in js with "+" operator, while in php you should use "."
So you can try this: (i didn't test it)
echo '<input type="button" onClick="location=''.$uid.'/'+this.form.menu.options[this.form.menu.selectedIndex].value;" value="GO">';
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
add a comment |
You can concatenate string in js with "+" operator, while in php you should use "."
So you can try this: (i didn't test it)
echo '<input type="button" onClick="location=''.$uid.'/'+this.form.menu.options[this.form.menu.selectedIndex].value;" value="GO">';
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
You can concatenate string in js with "+" operator, while in php you should use "."
So you can try this: (i didn't test it)
echo '<input type="button" onClick="location=''.$uid.'/'+this.form.menu.options[this.form.menu.selectedIndex].value;" value="GO">';
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
answered Jan 20 at 9:07
Eko SetiawanEko Setiawan
205
205
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2
HTML attributes, e.g.
onClick, must have their values enclosed within double quotes, e.g.onClick="your_code_goes_here". YouronClickis likely failing because you never added that in. Be sure to enclose theonClickJavaScript in double quotes, remembering to escape those quotes i.e. doonClick="your_code_goes_here". Other problems may or may not exist, but this one would definitely cause a major syntax error.– B. Fleming
Jan 20 at 0:38