SQL Force Left Join to Print No Match












0















I have a problem with a query. I have a bunch of cars, and there are types of cars. For each type, a user can select one car, and I'm saving this in the database. When I want to retrieve the data I run into trouble:



[
{
"id_typecar": 1,
"nom_typecar": "Type17",
"id_car": 14,
"id_user": 3,
"cars": [
{
"id_car": 1,
"nom_car": "775",
}
},
{
"id_car": 2,
"nom_car": "048",
}
]
},
{
//Not displayed if user_id != 1 or null -> I want to display that
"id_typecar": 2,
"nom_typecar": "Type1",
"id_car": 13,
"id_user": 1, //expected output "id_user": null
"cars": [
{
"id_car": 11,
"nom_car": "123",
},
{
"id_car": 12,
"nom_car": "456,
},
{
"id_car": 17,
"nom_car": "789",
}
]


And my query :



    return TypeCars::with('cars')
->leftJoin('cars_user', 'cars_user.id', '=', 'type_cars.id')
->where('cars_user.id' = 1)
->orWhereNull('cars_user.id')
->get()
->toJson();


I wanted to retrieve the data even if the id_user is not there yet because I must display types and cars. I added the leftJoin constraint with a where "null" or where cars_user.userid = ? but if user 3 chose one type of car that user 1 has not chosen (because it won't null or userid = 1), it would not display cars anymore.



Thank you!



EDIT :



Actual output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 2 Type2Car 13 |
| 2 Type2Car 13 |
| 3 Type3Car NULL |
+---------------------------------+


Expected output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 1 Type1Car NULL | <-- needed for the display
| 2 Type2Car 13 |
| 2 Type2Car 14 |
| 3 Type3Car NULL |
| 3 Type3Car NULL |
+---------------------------------+


If I don't have this line if the user 13 didn't specify any cars for this type it won't display since user 14 has chosen one










share|improve this question

























  • Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

    – Caius Jard
    Jan 19 at 12:53













  • I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

    – FlickaMin
    Jan 19 at 13:08











  • Why are you not complaining that type2car also has no null row?

    – Caius Jard
    Jan 19 at 13:14











  • I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

    – FlickaMin
    Jan 19 at 13:15











  • So you basically always want a null row for each car as well as non null rows showing cars that are booked?

    – Caius Jard
    Jan 19 at 13:16
















0















I have a problem with a query. I have a bunch of cars, and there are types of cars. For each type, a user can select one car, and I'm saving this in the database. When I want to retrieve the data I run into trouble:



[
{
"id_typecar": 1,
"nom_typecar": "Type17",
"id_car": 14,
"id_user": 3,
"cars": [
{
"id_car": 1,
"nom_car": "775",
}
},
{
"id_car": 2,
"nom_car": "048",
}
]
},
{
//Not displayed if user_id != 1 or null -> I want to display that
"id_typecar": 2,
"nom_typecar": "Type1",
"id_car": 13,
"id_user": 1, //expected output "id_user": null
"cars": [
{
"id_car": 11,
"nom_car": "123",
},
{
"id_car": 12,
"nom_car": "456,
},
{
"id_car": 17,
"nom_car": "789",
}
]


And my query :



    return TypeCars::with('cars')
->leftJoin('cars_user', 'cars_user.id', '=', 'type_cars.id')
->where('cars_user.id' = 1)
->orWhereNull('cars_user.id')
->get()
->toJson();


I wanted to retrieve the data even if the id_user is not there yet because I must display types and cars. I added the leftJoin constraint with a where "null" or where cars_user.userid = ? but if user 3 chose one type of car that user 1 has not chosen (because it won't null or userid = 1), it would not display cars anymore.



Thank you!



EDIT :



Actual output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 2 Type2Car 13 |
| 2 Type2Car 13 |
| 3 Type3Car NULL |
+---------------------------------+


Expected output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 1 Type1Car NULL | <-- needed for the display
| 2 Type2Car 13 |
| 2 Type2Car 14 |
| 3 Type3Car NULL |
| 3 Type3Car NULL |
+---------------------------------+


If I don't have this line if the user 13 didn't specify any cars for this type it won't display since user 14 has chosen one










share|improve this question

























  • Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

    – Caius Jard
    Jan 19 at 12:53













  • I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

    – FlickaMin
    Jan 19 at 13:08











  • Why are you not complaining that type2car also has no null row?

    – Caius Jard
    Jan 19 at 13:14











  • I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

    – FlickaMin
    Jan 19 at 13:15











  • So you basically always want a null row for each car as well as non null rows showing cars that are booked?

    – Caius Jard
    Jan 19 at 13:16














0












0








0








I have a problem with a query. I have a bunch of cars, and there are types of cars. For each type, a user can select one car, and I'm saving this in the database. When I want to retrieve the data I run into trouble:



[
{
"id_typecar": 1,
"nom_typecar": "Type17",
"id_car": 14,
"id_user": 3,
"cars": [
{
"id_car": 1,
"nom_car": "775",
}
},
{
"id_car": 2,
"nom_car": "048",
}
]
},
{
//Not displayed if user_id != 1 or null -> I want to display that
"id_typecar": 2,
"nom_typecar": "Type1",
"id_car": 13,
"id_user": 1, //expected output "id_user": null
"cars": [
{
"id_car": 11,
"nom_car": "123",
},
{
"id_car": 12,
"nom_car": "456,
},
{
"id_car": 17,
"nom_car": "789",
}
]


And my query :



    return TypeCars::with('cars')
->leftJoin('cars_user', 'cars_user.id', '=', 'type_cars.id')
->where('cars_user.id' = 1)
->orWhereNull('cars_user.id')
->get()
->toJson();


I wanted to retrieve the data even if the id_user is not there yet because I must display types and cars. I added the leftJoin constraint with a where "null" or where cars_user.userid = ? but if user 3 chose one type of car that user 1 has not chosen (because it won't null or userid = 1), it would not display cars anymore.



Thank you!



EDIT :



Actual output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 2 Type2Car 13 |
| 2 Type2Car 13 |
| 3 Type3Car NULL |
+---------------------------------+


Expected output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 1 Type1Car NULL | <-- needed for the display
| 2 Type2Car 13 |
| 2 Type2Car 14 |
| 3 Type3Car NULL |
| 3 Type3Car NULL |
+---------------------------------+


If I don't have this line if the user 13 didn't specify any cars for this type it won't display since user 14 has chosen one










share|improve this question
















I have a problem with a query. I have a bunch of cars, and there are types of cars. For each type, a user can select one car, and I'm saving this in the database. When I want to retrieve the data I run into trouble:



[
{
"id_typecar": 1,
"nom_typecar": "Type17",
"id_car": 14,
"id_user": 3,
"cars": [
{
"id_car": 1,
"nom_car": "775",
}
},
{
"id_car": 2,
"nom_car": "048",
}
]
},
{
//Not displayed if user_id != 1 or null -> I want to display that
"id_typecar": 2,
"nom_typecar": "Type1",
"id_car": 13,
"id_user": 1, //expected output "id_user": null
"cars": [
{
"id_car": 11,
"nom_car": "123",
},
{
"id_car": 12,
"nom_car": "456,
},
{
"id_car": 17,
"nom_car": "789",
}
]


And my query :



    return TypeCars::with('cars')
->leftJoin('cars_user', 'cars_user.id', '=', 'type_cars.id')
->where('cars_user.id' = 1)
->orWhereNull('cars_user.id')
->get()
->toJson();


I wanted to retrieve the data even if the id_user is not there yet because I must display types and cars. I added the leftJoin constraint with a where "null" or where cars_user.userid = ? but if user 3 chose one type of car that user 1 has not chosen (because it won't null or userid = 1), it would not display cars anymore.



Thank you!



EDIT :



Actual output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 2 Type2Car 13 |
| 2 Type2Car 13 |
| 3 Type3Car NULL |
+---------------------------------+


Expected output :



+---------------------------------+
| id_typecar name_typecar id_user |
+---------------------------------+
| 1 Type1Car 14 |
| 1 Type1Car NULL | <-- needed for the display
| 2 Type2Car 13 |
| 2 Type2Car 14 |
| 3 Type3Car NULL |
| 3 Type3Car NULL |
+---------------------------------+


If I don't have this line if the user 13 didn't specify any cars for this type it won't display since user 14 has chosen one







mysql sql laravel eloquent






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 19 at 13:37







FlickaMin

















asked Jan 19 at 12:03









FlickaMinFlickaMin

126




126













  • Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

    – Caius Jard
    Jan 19 at 12:53













  • I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

    – FlickaMin
    Jan 19 at 13:08











  • Why are you not complaining that type2car also has no null row?

    – Caius Jard
    Jan 19 at 13:14











  • I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

    – FlickaMin
    Jan 19 at 13:15











  • So you basically always want a null row for each car as well as non null rows showing cars that are booked?

    – Caius Jard
    Jan 19 at 13:16



















  • Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

    – Caius Jard
    Jan 19 at 12:53













  • I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

    – FlickaMin
    Jan 19 at 13:08











  • Why are you not complaining that type2car also has no null row?

    – Caius Jard
    Jan 19 at 13:14











  • I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

    – FlickaMin
    Jan 19 at 13:15











  • So you basically always want a null row for each car as well as non null rows showing cars that are booked?

    – Caius Jard
    Jan 19 at 13:16

















Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

– Caius Jard
Jan 19 at 12:53







Does the JSON somehow represent sample data of what is currently in your tables? Can you post a more easy-to-interpret version (flat text)

– Caius Jard
Jan 19 at 12:53















I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

– FlickaMin
Jan 19 at 13:08





I've updated with ASCII output about what is going on and what expected. It's pretty hard to explain, apologies if you don't understand, I'm trying to be as clear as possible but that's not easy

– FlickaMin
Jan 19 at 13:08













Why are you not complaining that type2car also has no null row?

– Caius Jard
Jan 19 at 13:14





Why are you not complaining that type2car also has no null row?

– Caius Jard
Jan 19 at 13:14













I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

– FlickaMin
Jan 19 at 13:15





I forgot to add it but that is the same for others in fact. I'm editing. Someone answered with an answer that was working very close from what I need but he unfortunaterly deleted it

– FlickaMin
Jan 19 at 13:15













So you basically always want a null row for each car as well as non null rows showing cars that are booked?

– Caius Jard
Jan 19 at 13:16





So you basically always want a null row for each car as well as non null rows showing cars that are booked?

– Caius Jard
Jan 19 at 13:16












1 Answer
1






active

oldest

votes


















0














Based on deleted answer, I solved my issue :



return TypeCars::with('cars')->leftJoin('user_cars', function($join){
$join->on('user_cars.id', '=', 'type_cars.id');
$join->on('user_cars.id', '=', DB::raw(1));
})
->whereNull('user_cars.id')
->where('user_cars.id', '=', 1)
->get()
->toJson();


DB::raw is needed to avoid Eloquent from quoting raw values.






share|improve this answer























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    1 Answer
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    1 Answer
    1






    active

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    active

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    active

    oldest

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    0














    Based on deleted answer, I solved my issue :



    return TypeCars::with('cars')->leftJoin('user_cars', function($join){
    $join->on('user_cars.id', '=', 'type_cars.id');
    $join->on('user_cars.id', '=', DB::raw(1));
    })
    ->whereNull('user_cars.id')
    ->where('user_cars.id', '=', 1)
    ->get()
    ->toJson();


    DB::raw is needed to avoid Eloquent from quoting raw values.






    share|improve this answer




























      0














      Based on deleted answer, I solved my issue :



      return TypeCars::with('cars')->leftJoin('user_cars', function($join){
      $join->on('user_cars.id', '=', 'type_cars.id');
      $join->on('user_cars.id', '=', DB::raw(1));
      })
      ->whereNull('user_cars.id')
      ->where('user_cars.id', '=', 1)
      ->get()
      ->toJson();


      DB::raw is needed to avoid Eloquent from quoting raw values.






      share|improve this answer


























        0












        0








        0







        Based on deleted answer, I solved my issue :



        return TypeCars::with('cars')->leftJoin('user_cars', function($join){
        $join->on('user_cars.id', '=', 'type_cars.id');
        $join->on('user_cars.id', '=', DB::raw(1));
        })
        ->whereNull('user_cars.id')
        ->where('user_cars.id', '=', 1)
        ->get()
        ->toJson();


        DB::raw is needed to avoid Eloquent from quoting raw values.






        share|improve this answer













        Based on deleted answer, I solved my issue :



        return TypeCars::with('cars')->leftJoin('user_cars', function($join){
        $join->on('user_cars.id', '=', 'type_cars.id');
        $join->on('user_cars.id', '=', DB::raw(1));
        })
        ->whereNull('user_cars.id')
        ->where('user_cars.id', '=', 1)
        ->get()
        ->toJson();


        DB::raw is needed to avoid Eloquent from quoting raw values.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 19 at 13:37









        FlickaMinFlickaMin

        126




        126






























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