pass content of contenteditable to input value and process in php












0















html code structure is as it follows a simple form



<form action="index.php" method="post" enctype="multipart/form-data">
<div contenteditable="true" id="post"></div>
<input type="text" name="postHiddenField" id="postHidden" hidden>
<button type="submit" name="submitPost">Post</button>
</form>


beneath the form the javascript is a simple atribute



var content = document.getElementById('post').innerHTML;
document.getElementById('postHidden').value = content;




on top of the form is the form being proccessed



<?php
if (isset($_POST['submitPost'])) {
if (!empty($_POST['postHiddenField'])) {
echo $_POST['postHiddenField'];
} else {
echo "field is empty";
}
}
?>


result i get on submission is field is empty
how to proper get content's editable content and pass it to the hidden field as value?










share|improve this question




















  • 5





    The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

    – Chris G
    yesterday











  • hey its working

    – andrew06041990
    yesterday











  • how secure is this practice?

    – andrew06041990
    yesterday






  • 1





    Can you be more specific?

    – Chris G
    yesterday






  • 3





    Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

    – Chris G
    yesterday
















0















html code structure is as it follows a simple form



<form action="index.php" method="post" enctype="multipart/form-data">
<div contenteditable="true" id="post"></div>
<input type="text" name="postHiddenField" id="postHidden" hidden>
<button type="submit" name="submitPost">Post</button>
</form>


beneath the form the javascript is a simple atribute



var content = document.getElementById('post').innerHTML;
document.getElementById('postHidden').value = content;




on top of the form is the form being proccessed



<?php
if (isset($_POST['submitPost'])) {
if (!empty($_POST['postHiddenField'])) {
echo $_POST['postHiddenField'];
} else {
echo "field is empty";
}
}
?>


result i get on submission is field is empty
how to proper get content's editable content and pass it to the hidden field as value?










share|improve this question




















  • 5





    The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

    – Chris G
    yesterday











  • hey its working

    – andrew06041990
    yesterday











  • how secure is this practice?

    – andrew06041990
    yesterday






  • 1





    Can you be more specific?

    – Chris G
    yesterday






  • 3





    Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

    – Chris G
    yesterday














0












0








0








html code structure is as it follows a simple form



<form action="index.php" method="post" enctype="multipart/form-data">
<div contenteditable="true" id="post"></div>
<input type="text" name="postHiddenField" id="postHidden" hidden>
<button type="submit" name="submitPost">Post</button>
</form>


beneath the form the javascript is a simple atribute



var content = document.getElementById('post').innerHTML;
document.getElementById('postHidden').value = content;




on top of the form is the form being proccessed



<?php
if (isset($_POST['submitPost'])) {
if (!empty($_POST['postHiddenField'])) {
echo $_POST['postHiddenField'];
} else {
echo "field is empty";
}
}
?>


result i get on submission is field is empty
how to proper get content's editable content and pass it to the hidden field as value?










share|improve this question
















html code structure is as it follows a simple form



<form action="index.php" method="post" enctype="multipart/form-data">
<div contenteditable="true" id="post"></div>
<input type="text" name="postHiddenField" id="postHidden" hidden>
<button type="submit" name="submitPost">Post</button>
</form>


beneath the form the javascript is a simple atribute



var content = document.getElementById('post').innerHTML;
document.getElementById('postHidden').value = content;




on top of the form is the form being proccessed



<?php
if (isset($_POST['submitPost'])) {
if (!empty($_POST['postHiddenField'])) {
echo $_POST['postHiddenField'];
} else {
echo "field is empty";
}
}
?>


result i get on submission is field is empty
how to proper get content's editable content and pass it to the hidden field as value?







javascript php html






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday









Ashay Mandwarya

1,062317




1,062317










asked yesterday









andrew06041990andrew06041990

227




227








  • 5





    The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

    – Chris G
    yesterday











  • hey its working

    – andrew06041990
    yesterday











  • how secure is this practice?

    – andrew06041990
    yesterday






  • 1





    Can you be more specific?

    – Chris G
    yesterday






  • 3





    Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

    – Chris G
    yesterday














  • 5





    The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

    – Chris G
    yesterday











  • hey its working

    – andrew06041990
    yesterday











  • how secure is this practice?

    – andrew06041990
    yesterday






  • 1





    Can you be more specific?

    – Chris G
    yesterday






  • 3





    Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

    – Chris G
    yesterday








5




5





The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

– Chris G
yesterday





The script you have is only executed exactly once, when the page loads. It doesn't magically extend into the future. If you wrap it in a function and set it as the form's onsubmit, it should work.

– Chris G
yesterday













hey its working

– andrew06041990
yesterday





hey its working

– andrew06041990
yesterday













how secure is this practice?

– andrew06041990
yesterday





how secure is this practice?

– andrew06041990
yesterday




1




1





Can you be more specific?

– Chris G
yesterday





Can you be more specific?

– Chris G
yesterday




3




3





Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

– Chris G
yesterday





Any JS browser code can be altered, yes. So you always have to validate all user input on the server, too. Especially when you're calling DB queries based on it.

– Chris G
yesterday












0






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