How to slice out column names based on column into row of new dataframe?
I have a df that looks like this
data.answers.1542213647002.subItemType data.answers.1542213647002.value.1542213647003
thank you for the response TRUE
How do I slice out the column name only for columns that have the string .value.
and the column has the value TRUE
into a new df like so?:
new_df
old_column_names
data.answers.1542213647002.value.1542213647003
I have roughly 100 more columns with .value.
in it but not all of them have TRUE in them as values.
python-3.x pandas
add a comment |
I have a df that looks like this
data.answers.1542213647002.subItemType data.answers.1542213647002.value.1542213647003
thank you for the response TRUE
How do I slice out the column name only for columns that have the string .value.
and the column has the value TRUE
into a new df like so?:
new_df
old_column_names
data.answers.1542213647002.value.1542213647003
I have roughly 100 more columns with .value.
in it but not all of them have TRUE in them as values.
python-3.x pandas
add a comment |
I have a df that looks like this
data.answers.1542213647002.subItemType data.answers.1542213647002.value.1542213647003
thank you for the response TRUE
How do I slice out the column name only for columns that have the string .value.
and the column has the value TRUE
into a new df like so?:
new_df
old_column_names
data.answers.1542213647002.value.1542213647003
I have roughly 100 more columns with .value.
in it but not all of them have TRUE in them as values.
python-3.x pandas
I have a df that looks like this
data.answers.1542213647002.subItemType data.answers.1542213647002.value.1542213647003
thank you for the response TRUE
How do I slice out the column name only for columns that have the string .value.
and the column has the value TRUE
into a new df like so?:
new_df
old_column_names
data.answers.1542213647002.value.1542213647003
I have roughly 100 more columns with .value.
in it but not all of them have TRUE in them as values.
python-3.x pandas
python-3.x pandas
edited Jan 19 at 18:35
RustyShackleford
asked Jan 19 at 18:15
RustyShacklefordRustyShackleford
1,178621
1,178621
add a comment |
add a comment |
1 Answer
1
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oldest
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assume this sample df:
df = pd.DataFrame({'col':[1,2]*5,
'col2.value.something':[True,False]*5,
'col3.value.something':[5]*10,
'col4':[True]*10})
then
# boolean indexing with stack
new = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
# drop duplicates
new = new.drop(columns=0).drop_duplicates()
1
0 col2.value.something
Thank you for the response: I get errorValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way:new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: isnew_df
already a dataframe or do you want that to be the variable name?
– Chris
Jan 19 at 18:56
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
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oldest
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active
oldest
votes
assume this sample df:
df = pd.DataFrame({'col':[1,2]*5,
'col2.value.something':[True,False]*5,
'col3.value.something':[5]*10,
'col4':[True]*10})
then
# boolean indexing with stack
new = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
# drop duplicates
new = new.drop(columns=0).drop_duplicates()
1
0 col2.value.something
Thank you for the response: I get errorValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way:new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: isnew_df
already a dataframe or do you want that to be the variable name?
– Chris
Jan 19 at 18:56
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
add a comment |
assume this sample df:
df = pd.DataFrame({'col':[1,2]*5,
'col2.value.something':[True,False]*5,
'col3.value.something':[5]*10,
'col4':[True]*10})
then
# boolean indexing with stack
new = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
# drop duplicates
new = new.drop(columns=0).drop_duplicates()
1
0 col2.value.something
Thank you for the response: I get errorValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way:new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: isnew_df
already a dataframe or do you want that to be the variable name?
– Chris
Jan 19 at 18:56
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
add a comment |
assume this sample df:
df = pd.DataFrame({'col':[1,2]*5,
'col2.value.something':[True,False]*5,
'col3.value.something':[5]*10,
'col4':[True]*10})
then
# boolean indexing with stack
new = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
# drop duplicates
new = new.drop(columns=0).drop_duplicates()
1
0 col2.value.something
assume this sample df:
df = pd.DataFrame({'col':[1,2]*5,
'col2.value.something':[True,False]*5,
'col3.value.something':[5]*10,
'col4':[True]*10})
then
# boolean indexing with stack
new = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
# drop duplicates
new = new.drop(columns=0).drop_duplicates()
1
0 col2.value.something
answered Jan 19 at 18:44
ChrisChris
2,4882420
2,4882420
Thank you for the response: I get errorValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way:new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: isnew_df
already a dataframe or do you want that to be the variable name?
– Chris
Jan 19 at 18:56
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
add a comment |
Thank you for the response: I get errorValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way:new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: isnew_df
already a dataframe or do you want that to be the variable name?
– Chris
Jan 19 at 18:56
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
Thank you for the response: I get error
ValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way: new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
Thank you for the response: I get error
ValueError: Wrong number of items passed 2, placement implies 1
when I run your line. I did it this way: new_df['new_col'] = pd.DataFrame(list(df[((df==True) & (df.columns.str.contains('.value.')))].stack().index))
– RustyShackleford
Jan 19 at 18:49
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
@RustyShackleford You are getting that error because you are trying to pass a dataframe with two columns and set it to one column in another dataframe
– Chris
Jan 19 at 18:51
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
anyway I can do your code the way I set it up?
– RustyShackleford
Jan 19 at 18:54
@RustyShackleford sure but I need some more information: is
new_df
already a dataframe or do you want that to be the variable name?– Chris
Jan 19 at 18:56
@RustyShackleford sure but I need some more information: is
new_df
already a dataframe or do you want that to be the variable name?– Chris
Jan 19 at 18:56
1
1
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
it is not a new df. However with your solution I recreated the dataframe with your logic and added the new rows. I dont think we need to rework the solution. Thank you so much
– RustyShackleford
Jan 19 at 19:01
add a comment |
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