Fortran's findloc with character type












3















I'm confused by the findloc intrinsic with a character array.
The program



print *, findloc(['AB'],'A',dim=1)
end


outputs



           1


while I expected 0.



I thought that findloc searched for equality, and 'A' /= 'AB'.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1) gives 0.



Note that findloc(['BA'],'A',dim=1) does give 0, so I don't think that findloc uses the index function.



I'm using ifort 18.0.3 on centos 7.










share|improve this question

























  • Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

    – A. Hennink
    Jan 18 at 17:45













  • Can you try with 19.0.1?

    – francescalus
    Jan 18 at 17:55











  • No, unfortunately not. And my version of gfortran is way too old.

    – A. Hennink
    Jan 18 at 17:57






  • 2





    Its just a compiler bug. You can report such things at supporttickets.intel.com.

    – IanH
    Jan 18 at 21:19






  • 2





    @francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

    – King
    Jan 20 at 0:03
















3















I'm confused by the findloc intrinsic with a character array.
The program



print *, findloc(['AB'],'A',dim=1)
end


outputs



           1


while I expected 0.



I thought that findloc searched for equality, and 'A' /= 'AB'.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1) gives 0.



Note that findloc(['BA'],'A',dim=1) does give 0, so I don't think that findloc uses the index function.



I'm using ifort 18.0.3 on centos 7.










share|improve this question

























  • Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

    – A. Hennink
    Jan 18 at 17:45













  • Can you try with 19.0.1?

    – francescalus
    Jan 18 at 17:55











  • No, unfortunately not. And my version of gfortran is way too old.

    – A. Hennink
    Jan 18 at 17:57






  • 2





    Its just a compiler bug. You can report such things at supporttickets.intel.com.

    – IanH
    Jan 18 at 21:19






  • 2





    @francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

    – King
    Jan 20 at 0:03














3












3








3


0






I'm confused by the findloc intrinsic with a character array.
The program



print *, findloc(['AB'],'A',dim=1)
end


outputs



           1


while I expected 0.



I thought that findloc searched for equality, and 'A' /= 'AB'.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1) gives 0.



Note that findloc(['BA'],'A',dim=1) does give 0, so I don't think that findloc uses the index function.



I'm using ifort 18.0.3 on centos 7.










share|improve this question
















I'm confused by the findloc intrinsic with a character array.
The program



print *, findloc(['AB'],'A',dim=1)
end


outputs



           1


while I expected 0.



I thought that findloc searched for equality, and 'A' /= 'AB'.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1) gives 0.



Note that findloc(['BA'],'A',dim=1) does give 0, so I don't think that findloc uses the index function.



I'm using ifort 18.0.3 on centos 7.







fortran intel-fortran






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 18 at 17:47







A. Hennink

















asked Jan 18 at 17:27









A. HenninkA. Hennink

121111




121111













  • Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

    – A. Hennink
    Jan 18 at 17:45













  • Can you try with 19.0.1?

    – francescalus
    Jan 18 at 17:55











  • No, unfortunately not. And my version of gfortran is way too old.

    – A. Hennink
    Jan 18 at 17:57






  • 2





    Its just a compiler bug. You can report such things at supporttickets.intel.com.

    – IanH
    Jan 18 at 21:19






  • 2





    @francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

    – King
    Jan 20 at 0:03



















  • Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

    – A. Hennink
    Jan 18 at 17:45













  • Can you try with 19.0.1?

    – francescalus
    Jan 18 at 17:55











  • No, unfortunately not. And my version of gfortran is way too old.

    – A. Hennink
    Jan 18 at 17:57






  • 2





    Its just a compiler bug. You can report such things at supporttickets.intel.com.

    – IanH
    Jan 18 at 21:19






  • 2





    @francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

    – King
    Jan 20 at 0:03

















Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

– A. Hennink
Jan 18 at 17:45







Yes, I used ifort -O0 -stand f08 -warn all -check all. And findloc is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.

– A. Hennink
Jan 18 at 17:45















Can you try with 19.0.1?

– francescalus
Jan 18 at 17:55





Can you try with 19.0.1?

– francescalus
Jan 18 at 17:55













No, unfortunately not. And my version of gfortran is way too old.

– A. Hennink
Jan 18 at 17:57





No, unfortunately not. And my version of gfortran is way too old.

– A. Hennink
Jan 18 at 17:57




2




2





Its just a compiler bug. You can report such things at supporttickets.intel.com.

– IanH
Jan 18 at 21:19





Its just a compiler bug. You can report such things at supporttickets.intel.com.

– IanH
Jan 18 at 21:19




2




2





@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

– King
Jan 20 at 0:03





@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.

– King
Jan 20 at 0:03












1 Answer
1






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oldest

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3














I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.






share|improve this answer








New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

    – A. Hennink
    yesterday











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.






share|improve this answer








New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

    – A. Hennink
    yesterday
















3














I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.






share|improve this answer








New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

    – A. Hennink
    yesterday














3












3








3







I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.






share|improve this answer








New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.







share|improve this answer








New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this answer



share|improve this answer






New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 2 days ago









R. GreenR. Green

461




461




New contributor




R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






R. Green is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

    – A. Hennink
    yesterday



















  • So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

    – A. Hennink
    yesterday

















So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

– A. Hennink
yesterday





So it's possible to write a 28-byte full program that triggers a bug: print*,findloc(['A'],'');end. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.

– A. Hennink
yesterday


















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