Fortran's findloc with character type
I'm confused by the findloc
intrinsic with a character array.
The program
print *, findloc(['AB'],'A',dim=1)
end
outputs
1
while I expected 0
.
I thought that findloc
searched for equality, and 'A' /= 'AB'
.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1)
gives 0
.
Note that findloc(['BA'],'A',dim=1)
does give 0
, so I don't think that findloc
uses the index
function.
I'm using ifort 18.0.3
on centos 7
.
fortran intel-fortran
add a comment |
I'm confused by the findloc
intrinsic with a character array.
The program
print *, findloc(['AB'],'A',dim=1)
end
outputs
1
while I expected 0
.
I thought that findloc
searched for equality, and 'A' /= 'AB'
.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1)
gives 0
.
Note that findloc(['BA'],'A',dim=1)
does give 0
, so I don't think that findloc
uses the index
function.
I'm using ifort 18.0.3
on centos 7
.
fortran intel-fortran
Yes, I usedifort -O0 -stand f08 -warn all -check all
. Andfindloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.
– A. Hennink
Jan 18 at 17:45
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
No, unfortunately not. And my version ofgfortran
is way too old.
– A. Hennink
Jan 18 at 17:57
2
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
2
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03
add a comment |
I'm confused by the findloc
intrinsic with a character array.
The program
print *, findloc(['AB'],'A',dim=1)
end
outputs
1
while I expected 0
.
I thought that findloc
searched for equality, and 'A' /= 'AB'
.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1)
gives 0
.
Note that findloc(['BA'],'A',dim=1)
does give 0
, so I don't think that findloc
uses the index
function.
I'm using ifort 18.0.3
on centos 7
.
fortran intel-fortran
I'm confused by the findloc
intrinsic with a character array.
The program
print *, findloc(['AB'],'A',dim=1)
end
outputs
1
while I expected 0
.
I thought that findloc
searched for equality, and 'A' /= 'AB'
.
If I make the scalar value of equal type as the array, then I do get what I expected: findloc(['AB'],'A ',dim=1)
gives 0
.
Note that findloc(['BA'],'A',dim=1)
does give 0
, so I don't think that findloc
uses the index
function.
I'm using ifort 18.0.3
on centos 7
.
fortran intel-fortran
fortran intel-fortran
edited Jan 18 at 17:47
A. Hennink
asked Jan 18 at 17:27
A. HenninkA. Hennink
121111
121111
Yes, I usedifort -O0 -stand f08 -warn all -check all
. Andfindloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.
– A. Hennink
Jan 18 at 17:45
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
No, unfortunately not. And my version ofgfortran
is way too old.
– A. Hennink
Jan 18 at 17:57
2
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
2
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03
add a comment |
Yes, I usedifort -O0 -stand f08 -warn all -check all
. Andfindloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.
– A. Hennink
Jan 18 at 17:45
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
No, unfortunately not. And my version ofgfortran
is way too old.
– A. Hennink
Jan 18 at 17:57
2
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
2
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03
Yes, I used
ifort -O0 -stand f08 -warn all -check all
. And findloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.– A. Hennink
Jan 18 at 17:45
Yes, I used
ifort -O0 -stand f08 -warn all -check all
. And findloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.– A. Hennink
Jan 18 at 17:45
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
No, unfortunately not. And my version of
gfortran
is way too old.– A. Hennink
Jan 18 at 17:57
No, unfortunately not. And my version of
gfortran
is way too old.– A. Hennink
Jan 18 at 17:57
2
2
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
2
2
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03
add a comment |
1 Answer
1
active
oldest
votes
I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.
New contributor
So it's possible to write a 28-byte full program that triggers a bug:print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.
– A. Hennink
yesterday
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.
New contributor
So it's possible to write a 28-byte full program that triggers a bug:print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.
– A. Hennink
yesterday
add a comment |
I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.
New contributor
So it's possible to write a 28-byte full program that triggers a bug:print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.
– A. Hennink
yesterday
add a comment |
I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.
New contributor
I agree that this is a bug in Intel Fortran's findloc() implementation. I created an Intel bug report to our developers.
New contributor
New contributor
answered 2 days ago
R. GreenR. Green
461
461
New contributor
New contributor
So it's possible to write a 28-byte full program that triggers a bug:print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.
– A. Hennink
yesterday
add a comment |
So it's possible to write a 28-byte full program that triggers a bug:print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.
– A. Hennink
yesterday
So it's possible to write a 28-byte full program that triggers a bug:
print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.– A. Hennink
yesterday
So it's possible to write a 28-byte full program that triggers a bug:
print*,findloc(['A'],'');end
. That must be some sort of record. But these things happen, and Fortran's characters are probably not the easiest to deal with. Thank you for letting us know.– A. Hennink
yesterday
add a comment |
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Yes, I used
ifort -O0 -stand f08 -warn all -check all
. Andfindloc
is Fortran 2008, so I'd be surprised if their implementation is old. Besides, I thought that this behavior would be standardized.– A. Hennink
Jan 18 at 17:45
Can you try with 19.0.1?
– francescalus
Jan 18 at 17:55
No, unfortunately not. And my version of
gfortran
is way too old.– A. Hennink
Jan 18 at 17:57
2
Its just a compiler bug. You can report such things at supporttickets.intel.com.
– IanH
Jan 18 at 21:19
2
@francescalus I tested this with Intel Fortran Compiler 2019, and the bug persists.
– King
Jan 20 at 0:03