How to flag duplicate values in r - newbie
I'm trying to flag duplicate IDs in another column. I don't necessarily want to remove them yet, just create an indicator (0/1) of whether the IDs are unique or duplicates. In sql, it would be like this:
SELECT ID
, count(ID
) count from TABLE
group by ID
) a
On TABLE
.ID
= a.ID
set ID Duplicate Flag Column 1
= 1
where count > 1;
Is there a way to do this simply in r?
Any help would be greatly appreciated.
r duplicates flags
add a comment |
I'm trying to flag duplicate IDs in another column. I don't necessarily want to remove them yet, just create an indicator (0/1) of whether the IDs are unique or duplicates. In sql, it would be like this:
SELECT ID
, count(ID
) count from TABLE
group by ID
) a
On TABLE
.ID
= a.ID
set ID Duplicate Flag Column 1
= 1
where count > 1;
Is there a way to do this simply in r?
Any help would be greatly appreciated.
r duplicates flags
3
Check?duplicated
.
– Ronak Shah
Jan 18 at 23:56
Like @RonakShah said. You can also usetable
andrle
.
– hmhensen
Jan 18 at 23:58
add a comment |
I'm trying to flag duplicate IDs in another column. I don't necessarily want to remove them yet, just create an indicator (0/1) of whether the IDs are unique or duplicates. In sql, it would be like this:
SELECT ID
, count(ID
) count from TABLE
group by ID
) a
On TABLE
.ID
= a.ID
set ID Duplicate Flag Column 1
= 1
where count > 1;
Is there a way to do this simply in r?
Any help would be greatly appreciated.
r duplicates flags
I'm trying to flag duplicate IDs in another column. I don't necessarily want to remove them yet, just create an indicator (0/1) of whether the IDs are unique or duplicates. In sql, it would be like this:
SELECT ID
, count(ID
) count from TABLE
group by ID
) a
On TABLE
.ID
= a.ID
set ID Duplicate Flag Column 1
= 1
where count > 1;
Is there a way to do this simply in r?
Any help would be greatly appreciated.
r duplicates flags
r duplicates flags
asked Jan 18 at 23:53
IanIan
61
61
3
Check?duplicated
.
– Ronak Shah
Jan 18 at 23:56
Like @RonakShah said. You can also usetable
andrle
.
– hmhensen
Jan 18 at 23:58
add a comment |
3
Check?duplicated
.
– Ronak Shah
Jan 18 at 23:56
Like @RonakShah said. You can also usetable
andrle
.
– hmhensen
Jan 18 at 23:58
3
3
Check
?duplicated
.– Ronak Shah
Jan 18 at 23:56
Check
?duplicated
.– Ronak Shah
Jan 18 at 23:56
Like @RonakShah said. You can also use
table
and rle
.– hmhensen
Jan 18 at 23:58
Like @RonakShah said. You can also use
table
and rle
.– hmhensen
Jan 18 at 23:58
add a comment |
1 Answer
1
active
oldest
votes
As an example of duplicated
let's start with some values (numbers here, but strings would do the same thing)
x <- c(9, 1:5, 3:7, 0:8)
x
# 9 1 2 3 4 5 3 4 5 6 7 0 1 2 3 4 5 6 7 8
If you want to flag the second and later copies
as.numeric(duplicated(x))
# 0 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 1 1 0
If you want to flag all values that occur two or more times
as.numeric(x %in% x[duplicated(x)])
# 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
As an example of duplicated
let's start with some values (numbers here, but strings would do the same thing)
x <- c(9, 1:5, 3:7, 0:8)
x
# 9 1 2 3 4 5 3 4 5 6 7 0 1 2 3 4 5 6 7 8
If you want to flag the second and later copies
as.numeric(duplicated(x))
# 0 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 1 1 0
If you want to flag all values that occur two or more times
as.numeric(x %in% x[duplicated(x)])
# 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
add a comment |
As an example of duplicated
let's start with some values (numbers here, but strings would do the same thing)
x <- c(9, 1:5, 3:7, 0:8)
x
# 9 1 2 3 4 5 3 4 5 6 7 0 1 2 3 4 5 6 7 8
If you want to flag the second and later copies
as.numeric(duplicated(x))
# 0 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 1 1 0
If you want to flag all values that occur two or more times
as.numeric(x %in% x[duplicated(x)])
# 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
add a comment |
As an example of duplicated
let's start with some values (numbers here, but strings would do the same thing)
x <- c(9, 1:5, 3:7, 0:8)
x
# 9 1 2 3 4 5 3 4 5 6 7 0 1 2 3 4 5 6 7 8
If you want to flag the second and later copies
as.numeric(duplicated(x))
# 0 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 1 1 0
If you want to flag all values that occur two or more times
as.numeric(x %in% x[duplicated(x)])
# 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0
As an example of duplicated
let's start with some values (numbers here, but strings would do the same thing)
x <- c(9, 1:5, 3:7, 0:8)
x
# 9 1 2 3 4 5 3 4 5 6 7 0 1 2 3 4 5 6 7 8
If you want to flag the second and later copies
as.numeric(duplicated(x))
# 0 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 1 1 0
If you want to flag all values that occur two or more times
as.numeric(x %in% x[duplicated(x)])
# 0 1 1 1 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 0
answered Jan 19 at 1:15
HenryHenry
5,21911633
5,21911633
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
add a comment |
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Ok, not really sure how to write that, or if that actually gives me what I'm looking for? I have nearly 1 million records and I just want to flag whether the 'unique' id is repeated (i.e., one column of data, not the entire row). I've tried the following, which I think gets me pretty close, but I get an error saying "replacement has xxx rows, data has xxx rows")
– Ian
Jan 22 at 18:40
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
Data$DupeFlagColumn[!duplicated(Data$Column)] <- 0
– Ian
Jan 22 at 18:41
add a comment |
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3
Check
?duplicated
.– Ronak Shah
Jan 18 at 23:56
Like @RonakShah said. You can also use
table
andrle
.– hmhensen
Jan 18 at 23:58