Kotlin KCallable illegalArgumentException
I have the following Kotlin function:
fun invokeSync(typedArguments : List<Any?>): Any?{
var returnedValue : Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e:Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
}
It doesn't matter how much arguments are in this list, I will always get an IllegalArgumentException saying "Callable expects 3 arguments, but 1 were provided".
The function is a simple isGreater-function with 2 arguments of type Int.
I have checked the list of arguments and there are 2 arguments of type Int in there.
Here the function in context:
open class TypedJavaScriptFunction(name: String) : SelfRegisteringJavascriptFunction(MessageFormat.format(JS_NAME_CONVENTION, name)) {
val callable = getCallable(this::class)
override fun function(arguments: Array<Any?>): Any? {
try {
val typedArguments = getTypedArguments(arguments)
val annotations = callable.annotations
for (a in annotations) {
if (a is BrowserFunction) {
if (a.value == Policy.ASYNC) {
invokeAsync(typedArguments);
return null
} else {
return invokeSync(typedArguments)
}
}
}
} catch (e: IllegalArgumentException) {
// this Exception is only for signaling the error; it has already
// been logged before
JavaScriptAPI.showError(browser, "Internal Error (" + callable.name + ")");
}
return null
}
fun getTypedArguments(arguments: Array<Any?>): List<Any?> {
var typedArguments = mutableListOf<Any?>()
val argTypes = callable.valueParameters
if (arguments.size != argTypes.size) {
LOG.error(getName()
+ ": given arguments don't match signature. Given: "
+ arguments.size + ", expected: " + argTypes.size);
throw IllegalArgumentException()
}
for (i in 0 until arguments.size) {
typedArguments.add(TypeRefinery.refine(arguments[i], argTypes[i].type.classifier as KClass<Any>))
}
return typedArguments
}
// ...
fun invokeSync(typedArguments: List<Any?>): Any? {
var returnedValue: Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e: Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
// ...
}
}
Did anyone can help me and tell me whats wrong or can give me a hint?
kotlin illegalargumentexception
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
add a comment |
I have the following Kotlin function:
fun invokeSync(typedArguments : List<Any?>): Any?{
var returnedValue : Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e:Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
}
It doesn't matter how much arguments are in this list, I will always get an IllegalArgumentException saying "Callable expects 3 arguments, but 1 were provided".
The function is a simple isGreater-function with 2 arguments of type Int.
I have checked the list of arguments and there are 2 arguments of type Int in there.
Here the function in context:
open class TypedJavaScriptFunction(name: String) : SelfRegisteringJavascriptFunction(MessageFormat.format(JS_NAME_CONVENTION, name)) {
val callable = getCallable(this::class)
override fun function(arguments: Array<Any?>): Any? {
try {
val typedArguments = getTypedArguments(arguments)
val annotations = callable.annotations
for (a in annotations) {
if (a is BrowserFunction) {
if (a.value == Policy.ASYNC) {
invokeAsync(typedArguments);
return null
} else {
return invokeSync(typedArguments)
}
}
}
} catch (e: IllegalArgumentException) {
// this Exception is only for signaling the error; it has already
// been logged before
JavaScriptAPI.showError(browser, "Internal Error (" + callable.name + ")");
}
return null
}
fun getTypedArguments(arguments: Array<Any?>): List<Any?> {
var typedArguments = mutableListOf<Any?>()
val argTypes = callable.valueParameters
if (arguments.size != argTypes.size) {
LOG.error(getName()
+ ": given arguments don't match signature. Given: "
+ arguments.size + ", expected: " + argTypes.size);
throw IllegalArgumentException()
}
for (i in 0 until arguments.size) {
typedArguments.add(TypeRefinery.refine(arguments[i], argTypes[i].type.classifier as KClass<Any>))
}
return typedArguments
}
// ...
fun invokeSync(typedArguments: List<Any?>): Any? {
var returnedValue: Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e: Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
// ...
}
}
Did anyone can help me and tell me whats wrong or can give me a hint?
kotlin illegalargumentexception
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
Can you show how you are definingcallablein this context?
– Todd
Jan 20 at 15:47
.. and howthis(surrounding class) is defined?
– Michael Butscher
Jan 20 at 15:50
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54
add a comment |
I have the following Kotlin function:
fun invokeSync(typedArguments : List<Any?>): Any?{
var returnedValue : Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e:Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
}
It doesn't matter how much arguments are in this list, I will always get an IllegalArgumentException saying "Callable expects 3 arguments, but 1 were provided".
The function is a simple isGreater-function with 2 arguments of type Int.
I have checked the list of arguments and there are 2 arguments of type Int in there.
Here the function in context:
open class TypedJavaScriptFunction(name: String) : SelfRegisteringJavascriptFunction(MessageFormat.format(JS_NAME_CONVENTION, name)) {
val callable = getCallable(this::class)
override fun function(arguments: Array<Any?>): Any? {
try {
val typedArguments = getTypedArguments(arguments)
val annotations = callable.annotations
for (a in annotations) {
if (a is BrowserFunction) {
if (a.value == Policy.ASYNC) {
invokeAsync(typedArguments);
return null
} else {
return invokeSync(typedArguments)
}
}
}
} catch (e: IllegalArgumentException) {
// this Exception is only for signaling the error; it has already
// been logged before
JavaScriptAPI.showError(browser, "Internal Error (" + callable.name + ")");
}
return null
}
fun getTypedArguments(arguments: Array<Any?>): List<Any?> {
var typedArguments = mutableListOf<Any?>()
val argTypes = callable.valueParameters
if (arguments.size != argTypes.size) {
LOG.error(getName()
+ ": given arguments don't match signature. Given: "
+ arguments.size + ", expected: " + argTypes.size);
throw IllegalArgumentException()
}
for (i in 0 until arguments.size) {
typedArguments.add(TypeRefinery.refine(arguments[i], argTypes[i].type.classifier as KClass<Any>))
}
return typedArguments
}
// ...
fun invokeSync(typedArguments: List<Any?>): Any? {
var returnedValue: Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e: Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
// ...
}
}
Did anyone can help me and tell me whats wrong or can give me a hint?
kotlin illegalargumentexception
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
I have the following Kotlin function:
fun invokeSync(typedArguments : List<Any?>): Any?{
var returnedValue : Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e:Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
}
It doesn't matter how much arguments are in this list, I will always get an IllegalArgumentException saying "Callable expects 3 arguments, but 1 were provided".
The function is a simple isGreater-function with 2 arguments of type Int.
I have checked the list of arguments and there are 2 arguments of type Int in there.
Here the function in context:
open class TypedJavaScriptFunction(name: String) : SelfRegisteringJavascriptFunction(MessageFormat.format(JS_NAME_CONVENTION, name)) {
val callable = getCallable(this::class)
override fun function(arguments: Array<Any?>): Any? {
try {
val typedArguments = getTypedArguments(arguments)
val annotations = callable.annotations
for (a in annotations) {
if (a is BrowserFunction) {
if (a.value == Policy.ASYNC) {
invokeAsync(typedArguments);
return null
} else {
return invokeSync(typedArguments)
}
}
}
} catch (e: IllegalArgumentException) {
// this Exception is only for signaling the error; it has already
// been logged before
JavaScriptAPI.showError(browser, "Internal Error (" + callable.name + ")");
}
return null
}
fun getTypedArguments(arguments: Array<Any?>): List<Any?> {
var typedArguments = mutableListOf<Any?>()
val argTypes = callable.valueParameters
if (arguments.size != argTypes.size) {
LOG.error(getName()
+ ": given arguments don't match signature. Given: "
+ arguments.size + ", expected: " + argTypes.size);
throw IllegalArgumentException()
}
for (i in 0 until arguments.size) {
typedArguments.add(TypeRefinery.refine(arguments[i], argTypes[i].type.classifier as KClass<Any>))
}
return typedArguments
}
// ...
fun invokeSync(typedArguments: List<Any?>): Any? {
var returnedValue: Any?
try {
returnedValue = callable.call(this, typedArguments);
} catch (e: Exception) {
logInvocationError(e, typedArguments);
throw IllegalArgumentException(e);
}
// ...
}
}
Did anyone can help me and tell me whats wrong or can give me a hint?
kotlin illegalargumentexception
kotlin illegalargumentexception
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
edited Jan 21 at 22:54
Willi Mentzel
9,862114770
9,862114770
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
asked Jan 20 at 15:22
Lucky OzzyLucky Ozzy
32
32
Can you show how you are definingcallablein this context?
– Todd
Jan 20 at 15:47
.. and howthis(surrounding class) is defined?
– Michael Butscher
Jan 20 at 15:50
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54
add a comment |
Can you show how you are definingcallablein this context?
– Todd
Jan 20 at 15:47
.. and howthis(surrounding class) is defined?
– Michael Butscher
Jan 20 at 15:50
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54
Can you show how you are defining
callable in this context?– Todd
Jan 20 at 15:47
Can you show how you are defining
callable in this context?– Todd
Jan 20 at 15:47
.. and how
this (surrounding class) is defined?– Michael Butscher
Jan 20 at 15:50
.. and how
this (surrounding class) is defined?– Michael Butscher
Jan 20 at 15:50
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54
add a comment |
1 Answer
1
active
oldest
votes
Since call takes a vararg you need to use the spread operator * and toTypedArray() to pass in the List like that:
returnedValue = callable.call(this, *typedArguments.toTypedArray());
The first argument is the instance you are calling the function on and the other two parameters come from the spreaded List, under the condition that List has exactly two elements.
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Since call takes a vararg you need to use the spread operator * and toTypedArray() to pass in the List like that:
returnedValue = callable.call(this, *typedArguments.toTypedArray());
The first argument is the instance you are calling the function on and the other two parameters come from the spreaded List, under the condition that List has exactly two elements.
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
add a comment |
Since call takes a vararg you need to use the spread operator * and toTypedArray() to pass in the List like that:
returnedValue = callable.call(this, *typedArguments.toTypedArray());
The first argument is the instance you are calling the function on and the other two parameters come from the spreaded List, under the condition that List has exactly two elements.
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
add a comment |
Since call takes a vararg you need to use the spread operator * and toTypedArray() to pass in the List like that:
returnedValue = callable.call(this, *typedArguments.toTypedArray());
The first argument is the instance you are calling the function on and the other two parameters come from the spreaded List, under the condition that List has exactly two elements.
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
Since call takes a vararg you need to use the spread operator * and toTypedArray() to pass in the List like that:
returnedValue = callable.call(this, *typedArguments.toTypedArray());
The first argument is the instance you are calling the function on and the other two parameters come from the spreaded List, under the condition that List has exactly two elements.
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
edited Jan 20 at 18:09
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
answered Jan 20 at 18:03
Willi MentzelWilli Mentzel
9,862114770
9,862114770
add a comment |
add a comment |
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Can you show how you are defining
callablein this context?– Todd
Jan 20 at 15:47
.. and how
this(surrounding class) is defined?– Michael Butscher
Jan 20 at 15:50
@Lucky Ozzy pls reduce it to a minimal example reproducing your problem. This way it is easier to spot the problem an help you.
– Willi Mentzel
Jan 20 at 17:54