Using jdb to step inside object construction during execution
I use jdb for my Java development. For my application I have two classes: WordUniverseTest and WordUniverse, and the main method is contained in WordUniverseTest. When I execute WordUniverseTest inside of jdb, I construct a WordUniverse object called obj inside of the main method.
But I do not know how to have jdb leave the WordUniverseTest class and step inside WordUniverse while obj is being constructed. How do I do this?
java debugging jdb
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
add a comment |
I use jdb for my Java development. For my application I have two classes: WordUniverseTest and WordUniverse, and the main method is contained in WordUniverseTest. When I execute WordUniverseTest inside of jdb, I construct a WordUniverse object called obj inside of the main method.
But I do not know how to have jdb leave the WordUniverseTest class and step inside WordUniverse while obj is being constructed. How do I do this?
java debugging jdb
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
add a comment |
I use jdb for my Java development. For my application I have two classes: WordUniverseTest and WordUniverse, and the main method is contained in WordUniverseTest. When I execute WordUniverseTest inside of jdb, I construct a WordUniverse object called obj inside of the main method.
But I do not know how to have jdb leave the WordUniverseTest class and step inside WordUniverse while obj is being constructed. How do I do this?
java debugging jdb
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
I use jdb for my Java development. For my application I have two classes: WordUniverseTest and WordUniverse, and the main method is contained in WordUniverseTest. When I execute WordUniverseTest inside of jdb, I construct a WordUniverse object called obj inside of the main method.
But I do not know how to have jdb leave the WordUniverseTest class and step inside WordUniverse while obj is being constructed. How do I do this?
java debugging jdb
java debugging jdb
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
asked Jan 20 at 15:31
Tomislav OstojichTomislav Ostojich
189
189
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can put a regular breakpoint there stop at and then when you are actually on the line (call list to verify), you can call step into.
As long as all your classes are known to jdb, it is going to work, I tested it.
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
I tried this and gotStep completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1but thejdbdidn't take me to the constructor.
– Tomislav Ostojich
Jan 20 at 19:58
When you call alistafterwards, you should see, that you are in the constructor. What do you see instead?
– Gergely Bacso
Jan 20 at 20:00
add a comment |
I found the answer, and although Gergely Bacso didn't give the full answer, he did lead me to find the full answer.
jdb uses a different procedure for stepping into methods versus stepping into constructors. To step into a method, you have to do what Gergely Basco said, which is set a breakpoint at where the method is called and then step into. But for stepping into a constructor you must say stop in ClassName.<init> (with brackets). Saying that command will take you inside of the constructor.
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can put a regular breakpoint there stop at and then when you are actually on the line (call list to verify), you can call step into.
As long as all your classes are known to jdb, it is going to work, I tested it.
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
I tried this and gotStep completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1but thejdbdidn't take me to the constructor.
– Tomislav Ostojich
Jan 20 at 19:58
When you call alistafterwards, you should see, that you are in the constructor. What do you see instead?
– Gergely Bacso
Jan 20 at 20:00
add a comment |
You can put a regular breakpoint there stop at and then when you are actually on the line (call list to verify), you can call step into.
As long as all your classes are known to jdb, it is going to work, I tested it.
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
I tried this and gotStep completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1but thejdbdidn't take me to the constructor.
– Tomislav Ostojich
Jan 20 at 19:58
When you call alistafterwards, you should see, that you are in the constructor. What do you see instead?
– Gergely Bacso
Jan 20 at 20:00
add a comment |
You can put a regular breakpoint there stop at and then when you are actually on the line (call list to verify), you can call step into.
As long as all your classes are known to jdb, it is going to work, I tested it.
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
You can put a regular breakpoint there stop at and then when you are actually on the line (call list to verify), you can call step into.
As long as all your classes are known to jdb, it is going to work, I tested it.
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
answered Jan 20 at 19:38
Gergely BacsoGergely Bacso
10.1k12952
10.1k12952
I tried this and gotStep completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1but thejdbdidn't take me to the constructor.
– Tomislav Ostojich
Jan 20 at 19:58
When you call alistafterwards, you should see, that you are in the constructor. What do you see instead?
– Gergely Bacso
Jan 20 at 20:00
add a comment |
I tried this and gotStep completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1but thejdbdidn't take me to the constructor.
– Tomislav Ostojich
Jan 20 at 19:58
When you call alistafterwards, you should see, that you are in the constructor. What do you see instead?
– Gergely Bacso
Jan 20 at 20:00
I tried this and got
Step completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1 but the jdb didn't take me to the constructor.– Tomislav Ostojich
Jan 20 at 19:58
I tried this and got
Step completed: "thread=main", jdk.internal.loader.BuiltinClassLoader.loadClass(), line=581 bci=1 but the jdb didn't take me to the constructor.– Tomislav Ostojich
Jan 20 at 19:58
When you call a
list afterwards, you should see, that you are in the constructor. What do you see instead?– Gergely Bacso
Jan 20 at 20:00
When you call a
list afterwards, you should see, that you are in the constructor. What do you see instead?– Gergely Bacso
Jan 20 at 20:00
add a comment |
I found the answer, and although Gergely Bacso didn't give the full answer, he did lead me to find the full answer.
jdb uses a different procedure for stepping into methods versus stepping into constructors. To step into a method, you have to do what Gergely Basco said, which is set a breakpoint at where the method is called and then step into. But for stepping into a constructor you must say stop in ClassName.<init> (with brackets). Saying that command will take you inside of the constructor.
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
add a comment |
I found the answer, and although Gergely Bacso didn't give the full answer, he did lead me to find the full answer.
jdb uses a different procedure for stepping into methods versus stepping into constructors. To step into a method, you have to do what Gergely Basco said, which is set a breakpoint at where the method is called and then step into. But for stepping into a constructor you must say stop in ClassName.<init> (with brackets). Saying that command will take you inside of the constructor.
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
add a comment |
I found the answer, and although Gergely Bacso didn't give the full answer, he did lead me to find the full answer.
jdb uses a different procedure for stepping into methods versus stepping into constructors. To step into a method, you have to do what Gergely Basco said, which is set a breakpoint at where the method is called and then step into. But for stepping into a constructor you must say stop in ClassName.<init> (with brackets). Saying that command will take you inside of the constructor.
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
I found the answer, and although Gergely Bacso didn't give the full answer, he did lead me to find the full answer.
jdb uses a different procedure for stepping into methods versus stepping into constructors. To step into a method, you have to do what Gergely Basco said, which is set a breakpoint at where the method is called and then step into. But for stepping into a constructor you must say stop in ClassName.<init> (with brackets). Saying that command will take you inside of the constructor.
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
answered Jan 20 at 20:04
Tomislav OstojichTomislav Ostojich
189
189
add a comment |
add a comment |
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