Why the “Uncaught ReferenceError:” when making my HTTP request?
0
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();See link below for a screenshot of the errors, but here's what I'm getting:
- An Uncaught ReferenceError on line 12 where my onreadystatechange is.
- I also get an error saying 'responseMethod' isn't defined at
makeRequest nor when I call it. - Also getting an error on the very last line for some reason.
javascript
edited Jan 20 at 1:06
melpomene
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
add a comment |
0
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();See link below for a screenshot of the errors, but here's what I'm getting:
- An Uncaught ReferenceError on line 12 where my onreadystatechange is.
- I also get an error saying 'responseMethod' isn't defined at
makeRequest nor when I call it. - Also getting an error on the very last line for some reason.
javascript
edited Jan 20 at 1:06
melpomene
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
You're not getting three different errors.Uncaught ReferenceError: responseMethod is not definedis a single error message.
– melpomene
Jan 20 at 1:07
add a comment |
0
0
0
0
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();See link below for a screenshot of the errors, but here's what I'm getting:
- An Uncaught ReferenceError on line 12 where my onreadystatechange is.
- I also get an error saying 'responseMethod' isn't defined at
makeRequest nor when I call it. - Also getting an error on the very last line for some reason.
javascript
edited Jan 20 at 1:06
melpomene
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();See link below for a screenshot of the errors, but here's what I'm getting:
- An Uncaught ReferenceError on line 12 where my onreadystatechange is.
- I also get an error saying 'responseMethod' isn't defined at
makeRequest nor when I call it. - Also getting an error on the very last line for some reason.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "OMMITTED FOR PRIVACY REASONS"; // Replace "APIKEY" with your own API key; otherwise, your HTTP request will not work
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();javascript
javascript
edited Jan 20 at 1:06
melpomene
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
edited Jan 20 at 1:06
melpomene
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
edited Jan 20 at 1:06
melpomene
60.3k54693
edited Jan 20 at 1:06
melpomene
60.3k54693
edited Jan 20 at 1:06
melpomene
60.3k54693
60.3k54693
asked Jan 20 at 0:11
MichaelMichael
33
asked Jan 20 at 0:11
MichaelMichael
33
asked Jan 20 at 0:11
MichaelMichael
33
33
The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
You're not getting three different errors.Uncaught ReferenceError: responseMethod is not definedis a single error message.
– melpomene
Jan 20 at 1:07
add a comment |
The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
You're not getting three different errors.Uncaught ReferenceError: responseMethod is not definedis a single error message.
– melpomene
Jan 20 at 1:07
The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
You're not getting three different errors.
Uncaught ReferenceError: responseMethod is not defined is a single error message.– melpomene
Jan 20 at 1:07
You're not getting three different errors.
Uncaught ReferenceError: responseMethod is not defined is a single error message.– melpomene
Jan 20 at 1:07
add a comment |
1 Answer
1
active
oldest
votes
0
Your code looks good. I just replaced your code with my api key and everything worked (see below).
Can you be more specific about the browser where you get an error?
I tried in the latest chrome and firefox and there is no problem.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();answered Jan 20 at 3:13
sanjeevsanjeev
8114
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
add a comment |
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1 Answer
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
Your code looks good. I just replaced your code with my api key and everything worked (see below).
Can you be more specific about the browser where you get an error?
I tried in the latest chrome and firefox and there is no problem.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();answered Jan 20 at 3:13
sanjeevsanjeev
8114
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
add a comment |
0
Your code looks good. I just replaced your code with my api key and everything worked (see below).
Can you be more specific about the browser where you get an error?
I tried in the latest chrome and firefox and there is no problem.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();answered Jan 20 at 3:13
sanjeevsanjeev
8114
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
add a comment |
0
0
0
Your code looks good. I just replaced your code with my api key and everything worked (see below).
Can you be more specific about the browser where you get an error?
I tried in the latest chrome and firefox and there is no problem.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();answered Jan 20 at 3:13
sanjeevsanjeev
8114
Your code looks good. I just replaced your code with my api key and everything worked (see below).
Can you be more specific about the browser where you get an error?
I tried in the latest chrome and firefox and there is no problem.
"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();"use strict";
(function() {
var url = "http://api.openweathermap.org/data/2.5/weather?q=London,England";
var apiKey = "4ff5002c91520701ec111b6082de9387"; // This key might expire soon.
var httpRequest;
makeRequest();
// create and send an XHR request
function makeRequest() {
httpRequest = new XMLHttpRequest();
httpRequest.onreadystatechange = responseMethod;
httpRequest.open('GET', url + '&appid=' + apiKey);
httpRequest.send();
}
// handle XHR response
function responseMethod() {
if (httpRequest.readyState === 4) {
console.log(httpRequest.responseText);
}
}
})();answered Jan 20 at 3:13
sanjeevsanjeev
8114
answered Jan 20 at 3:13
sanjeevsanjeev
8114
answered Jan 20 at 3:13
sanjeevsanjeev
8114
answered Jan 20 at 3:13
sanjeevsanjeev
8114
8114
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
add a comment |
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
I'm using Chrome as well. localhost:3000 I'm just as stumped as anyone else here. For what it's worth this is what I'm practicing with: linkedin.com/learning/building-web-applications-with-ajax/…
– Michael
Jan 20 at 20:45
add a comment |
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The code looks correct and works with another api, for example: pokeapi.co/api/v2/pokemon/ditto
– Bergur
Jan 20 at 0:47
You're not getting three different errors.
Uncaught ReferenceError: responseMethod is not definedis a single error message.– melpomene
Jan 20 at 1:07