How To Deserialize xml File programically without System.Configuration

I have xml file with this code

<configuration>



  <startup>

       <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5"/> 

  </startup>



  <applicationSettings>

       <GlobalERP.UI.Properties.Settings>

           <setting name="SQLServerIP" serializeAs="String">

              <value>192.168.1.1</value>

           </setting>

           <setting name="SQLUserName" serializeAs="String">

              <value>sa</value>

           </setting>

           <setting name="SQLPassword" serializeAs="String">

              <value>123</value>

           </setting>

           <setting name="SQLDBName" serializeAs="String">

               <value />

           </setting>

       </GlobalERP.UI.Properties.Settings>

   </applicationSettings>

</configuration>

How to deserialize and get value by name like "SQLServerIP" or "SQLUserName" by code and read lines without System.Configuration?

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

stackoverflow.com/questions/13043530/…

– Mary
Jan 19 at 6:32

by read all of string not use System.Configuration

– xxxsenatorxxx
Jan 19 at 6:35

1

That's not well-formed XML, try uploading it to xmlvalidation.com and you will get errors. That being said, if you just need to quickly parse some XML and pick out some values you can use LINQ to XML; see How does one parse XML files? or LINQ to read XML.

– dbc
Jan 19 at 6:43

1

@xxxsenatorxxx - which link? I posted two. Anyway, using LINQ to XML you can query deeply nested elements as shown in LINQ to XML extract nested elements, LINQ to XML nested elements query or Accessing nested elements while iterating an XML LINQ query?. Maybe you could provide a Minimal, Complete, and Verifiable example if those general answers aren't sufficient?

– dbc
Jan 19 at 7:42

1

And if you want to query a nested element based on an attribute value (here name="SQLServerIP" for instance) see LINQ to XML - Get element based on a nested elements value or Parsing XML Files in .NET.

– dbc
Jan 19 at 7:51

|
show 2 more comments

I have xml file with this code

<configuration>



  <startup>

       <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5"/> 

  </startup>



  <applicationSettings>

       <GlobalERP.UI.Properties.Settings>

           <setting name="SQLServerIP" serializeAs="String">

              <value>192.168.1.1</value>

           </setting>

           <setting name="SQLUserName" serializeAs="String">

              <value>sa</value>

           </setting>

           <setting name="SQLPassword" serializeAs="String">

              <value>123</value>

           </setting>

           <setting name="SQLDBName" serializeAs="String">

               <value />

           </setting>

       </GlobalERP.UI.Properties.Settings>

   </applicationSettings>

</configuration>

How to deserialize and get value by name like "SQLServerIP" or "SQLUserName" by code and read lines without System.Configuration?

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

stackoverflow.com/questions/13043530/…

– Mary
Jan 19 at 6:32

by read all of string not use System.Configuration

– xxxsenatorxxx
Jan 19 at 6:35

1

That's not well-formed XML, try uploading it to xmlvalidation.com and you will get errors. That being said, if you just need to quickly parse some XML and pick out some values you can use LINQ to XML; see How does one parse XML files? or LINQ to read XML.

– dbc
Jan 19 at 6:43

1

@xxxsenatorxxx - which link? I posted two. Anyway, using LINQ to XML you can query deeply nested elements as shown in LINQ to XML extract nested elements, LINQ to XML nested elements query or Accessing nested elements while iterating an XML LINQ query?. Maybe you could provide a Minimal, Complete, and Verifiable example if those general answers aren't sufficient?

– dbc
Jan 19 at 7:42

1

And if you want to query a nested element based on an attribute value (here name="SQLServerIP" for instance) see LINQ to XML - Get element based on a nested elements value or Parsing XML Files in .NET.

– dbc
Jan 19 at 7:51

|
show 2 more comments

I have xml file with this code

<configuration>



  <startup>

       <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5"/> 

  </startup>



  <applicationSettings>

       <GlobalERP.UI.Properties.Settings>

           <setting name="SQLServerIP" serializeAs="String">

              <value>192.168.1.1</value>

           </setting>

           <setting name="SQLUserName" serializeAs="String">

              <value>sa</value>

           </setting>

           <setting name="SQLPassword" serializeAs="String">

              <value>123</value>

           </setting>

           <setting name="SQLDBName" serializeAs="String">

               <value />

           </setting>

       </GlobalERP.UI.Properties.Settings>

   </applicationSettings>

</configuration>

How to deserialize and get value by name like "SQLServerIP" or "SQLUserName" by code and read lines without System.Configuration?

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

I have xml file with this code

<configuration>



  <startup>

       <supportedRuntime version="v4.0" sku=".NETFramework,Version=v4.5"/> 

  </startup>



  <applicationSettings>

       <GlobalERP.UI.Properties.Settings>

           <setting name="SQLServerIP" serializeAs="String">

              <value>192.168.1.1</value>

           </setting>

           <setting name="SQLUserName" serializeAs="String">

              <value>sa</value>

           </setting>

           <setting name="SQLPassword" serializeAs="String">

              <value>123</value>

           </setting>

           <setting name="SQLDBName" serializeAs="String">

               <value />

           </setting>

       </GlobalERP.UI.Properties.Settings>

   </applicationSettings>

</configuration>

How to deserialize and get value by name like "SQLServerIP" or "SQLUserName" by code and read lines without System.Configuration?

c# xml

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

edited Jan 19 at 7:32

Manoj Choudhari

1,234215

asked Jan 19 at 6:27

xxxsenatorxxx

479

asked Jan 19 at 6:27

xxxsenatorxxx

479

asked Jan 19 at 6:27

xxxsenatorxxx

479

stackoverflow.com/questions/13043530/…

– Mary
Jan 19 at 6:32

by read all of string not use System.Configuration

– xxxsenatorxxx
Jan 19 at 6:35

1

That's not well-formed XML, try uploading it to xmlvalidation.com and you will get errors. That being said, if you just need to quickly parse some XML and pick out some values you can use LINQ to XML; see How does one parse XML files? or LINQ to read XML.

– dbc
Jan 19 at 6:43

1

@xxxsenatorxxx - which link? I posted two. Anyway, using LINQ to XML you can query deeply nested elements as shown in LINQ to XML extract nested elements, LINQ to XML nested elements query or Accessing nested elements while iterating an XML LINQ query?. Maybe you could provide a Minimal, Complete, and Verifiable example if those general answers aren't sufficient?

– dbc
Jan 19 at 7:42

1

And if you want to query a nested element based on an attribute value (here name="SQLServerIP" for instance) see LINQ to XML - Get element based on a nested elements value or Parsing XML Files in .NET.

– dbc
Jan 19 at 7:51

|
show 2 more comments

stackoverflow.com/questions/13043530/…

– Mary
Jan 19 at 6:32

by read all of string not use System.Configuration

– xxxsenatorxxx
Jan 19 at 6:35

1

That's not well-formed XML, try uploading it to xmlvalidation.com and you will get errors. That being said, if you just need to quickly parse some XML and pick out some values you can use LINQ to XML; see How does one parse XML files? or LINQ to read XML.

– dbc
Jan 19 at 6:43

1

@xxxsenatorxxx - which link? I posted two. Anyway, using LINQ to XML you can query deeply nested elements as shown in LINQ to XML extract nested elements, LINQ to XML nested elements query or Accessing nested elements while iterating an XML LINQ query?. Maybe you could provide a Minimal, Complete, and Verifiable example if those general answers aren't sufficient?

– dbc
Jan 19 at 7:42

1

And if you want to query a nested element based on an attribute value (here name="SQLServerIP" for instance) see LINQ to XML - Get element based on a nested elements value or Parsing XML Files in .NET.

– dbc
Jan 19 at 7:51

stackoverflow.com/questions/13043530/…

– Mary
Jan 19 at 6:32

by read all of string not use System.Configuration

– xxxsenatorxxx
Jan 19 at 6:35

That's not well-formed XML, try uploading it to xmlvalidation.com and you will get errors. That being said, if you just need to quickly parse some XML and pick out some values you can use LINQ to XML; see How does one parse XML files? or LINQ to read XML.

– dbc
Jan 19 at 6:43

@xxxsenatorxxx - which link? I posted two. Anyway, using LINQ to XML you can query deeply nested elements as shown in LINQ to XML extract nested elements, LINQ to XML nested elements query or Accessing nested elements while iterating an XML LINQ query?. Maybe you could provide a Minimal, Complete, and Verifiable example if those general answers aren't sufficient?

– dbc
Jan 19 at 7:42

And if you want to query a nested element based on an attribute value (here name="SQLServerIP" for instance) see LINQ to XML - Get element based on a nested elements value or Parsing XML Files in .NET.

– dbc
Jan 19 at 7:51

|
show 2 more comments

1 Answer
1

active

oldest

votes

I find Best
Answer
with an small edit

 XmlDocument doc = new XmlDocument();

            doc.Load(path);

            XmlNodeList elemList = doc.GetElementsByTagName("setting");

            for (int i = 0; i < elemList.Count; i++)

            {

                if (elemList[i].Attributes["name"].Value == "UserName")

                {

                    textBox1.Text += elemList[i].InnerText;

                }

            }

answered Jan 19 at 9:07

xxxsenatorxxx

479

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

I find Best
Answer
with an small edit

 XmlDocument doc = new XmlDocument();

            doc.Load(path);

            XmlNodeList elemList = doc.GetElementsByTagName("setting");

            for (int i = 0; i < elemList.Count; i++)

            {

                if (elemList[i].Attributes["name"].Value == "UserName")

                {

                    textBox1.Text += elemList[i].InnerText;

                }

            }

answered Jan 19 at 9:07

xxxsenatorxxx

479

add a comment |

I find Best
Answer
with an small edit

 XmlDocument doc = new XmlDocument();

            doc.Load(path);

            XmlNodeList elemList = doc.GetElementsByTagName("setting");

            for (int i = 0; i < elemList.Count; i++)

            {

                if (elemList[i].Attributes["name"].Value == "UserName")

                {

                    textBox1.Text += elemList[i].InnerText;

                }

            }

answered Jan 19 at 9:07

xxxsenatorxxx

479

add a comment |

I find Best
Answer
with an small edit

 XmlDocument doc = new XmlDocument();

            doc.Load(path);

            XmlNodeList elemList = doc.GetElementsByTagName("setting");

            for (int i = 0; i < elemList.Count; i++)

            {

                if (elemList[i].Attributes["name"].Value == "UserName")

                {

                    textBox1.Text += elemList[i].InnerText;

                }

            }

answered Jan 19 at 9:07

xxxsenatorxxx

479

I find Best
Answer
with an small edit

 XmlDocument doc = new XmlDocument();

            doc.Load(path);

            XmlNodeList elemList = doc.GetElementsByTagName("setting");

            for (int i = 0; i < elemList.Count; i++)

            {

                if (elemList[i].Attributes["name"].Value == "UserName")

                {

                    textBox1.Text += elemList[i].InnerText;

                }

            }

answered Jan 19 at 9:07

xxxsenatorxxx

479

answered Jan 19 at 9:07

xxxsenatorxxx

479

answered Jan 19 at 9:07

xxxsenatorxxx

479

answered Jan 19 at 9:07

xxxsenatorxxx

479

add a comment |

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