Is there way to get anything in ajax success response with MVC action returning emptyresult()
i have a controller action e.g create() that returns emptyresult() in it after doing some back end work . i am calling my create() action through ajax . Now if the back-end work is successful i want to do something back in jquery in ajax success . How should i do that ?
public ActionResult Create(string id)
{
//does something
return new EmptyResult();
}
and i want to do something in my ajax success portion now
$.ajax({
type: "POST",
url: "@Url.Action("Create", "controller")",
data: "{Id:'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
cache: false,
success: function (response) {
alert();
$("#getoptionSp").empty();
$("#getoptionSp").append("<div>Pending<div>");
},
error: function () {
}
})
i want to change the front end with jquery .. how can i do this if action return empty result . i cant return view it will be messier for the code .
ajax asp.net-mvc asp.net-mvc-4
add a comment |
i have a controller action e.g create() that returns emptyresult() in it after doing some back end work . i am calling my create() action through ajax . Now if the back-end work is successful i want to do something back in jquery in ajax success . How should i do that ?
public ActionResult Create(string id)
{
//does something
return new EmptyResult();
}
and i want to do something in my ajax success portion now
$.ajax({
type: "POST",
url: "@Url.Action("Create", "controller")",
data: "{Id:'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
cache: false,
success: function (response) {
alert();
$("#getoptionSp").empty();
$("#getoptionSp").append("<div>Pending<div>");
},
error: function () {
}
})
i want to change the front end with jquery .. how can i do this if action return empty result . i cant return view it will be messier for the code .
ajax asp.net-mvc asp.net-mvc-4
add a comment |
i have a controller action e.g create() that returns emptyresult() in it after doing some back end work . i am calling my create() action through ajax . Now if the back-end work is successful i want to do something back in jquery in ajax success . How should i do that ?
public ActionResult Create(string id)
{
//does something
return new EmptyResult();
}
and i want to do something in my ajax success portion now
$.ajax({
type: "POST",
url: "@Url.Action("Create", "controller")",
data: "{Id:'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
cache: false,
success: function (response) {
alert();
$("#getoptionSp").empty();
$("#getoptionSp").append("<div>Pending<div>");
},
error: function () {
}
})
i want to change the front end with jquery .. how can i do this if action return empty result . i cant return view it will be messier for the code .
ajax asp.net-mvc asp.net-mvc-4
i have a controller action e.g create() that returns emptyresult() in it after doing some back end work . i am calling my create() action through ajax . Now if the back-end work is successful i want to do something back in jquery in ajax success . How should i do that ?
public ActionResult Create(string id)
{
//does something
return new EmptyResult();
}
and i want to do something in my ajax success portion now
$.ajax({
type: "POST",
url: "@Url.Action("Create", "controller")",
data: "{Id:'" + id + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
async: false,
cache: false,
success: function (response) {
alert();
$("#getoptionSp").empty();
$("#getoptionSp").append("<div>Pending<div>");
},
error: function () {
}
})
i want to change the front end with jquery .. how can i do this if action return empty result . i cant return view it will be messier for the code .
ajax asp.net-mvc asp.net-mvc-4
ajax asp.net-mvc asp.net-mvc-4
asked 2 days ago
haroon nasirharoon nasir
12410
12410
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
well i got the answer while trying just return
return Json("",JsonRequestBehavior.AllowGet);
and we are good to go for the ajax success response .
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
well i got the answer while trying just return
return Json("",JsonRequestBehavior.AllowGet);
and we are good to go for the ajax success response .
add a comment |
well i got the answer while trying just return
return Json("",JsonRequestBehavior.AllowGet);
and we are good to go for the ajax success response .
add a comment |
well i got the answer while trying just return
return Json("",JsonRequestBehavior.AllowGet);
and we are good to go for the ajax success response .
well i got the answer while trying just return
return Json("",JsonRequestBehavior.AllowGet);
and we are good to go for the ajax success response .
answered 2 days ago
haroon nasirharoon nasir
12410
12410
add a comment |
add a comment |
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