Python send my e-email to gmail, but not send to outlook or work address
My python code send a e-mail from my work aaddress to my gmail address, but they not send to any outlook address or work address.
When I send the email it appears in the sent box, regardless of whether it was delivered or not.
import smtplib
import mimetypes
import email
import email.mime.application
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
_from = 'myaddress@work.com.br'
_pass = 'pass'
_to = ['mygmail@gmail.com','myaddress@work.com.br']
msg = email.mime.multipart.MIMEMultipart()
msg['Subject'] = 'Test'
msg['From'] = 'myaddress@work.com.br'
msg['To'] = ", ".join(_to)
body = MIMEText('Hi, this is a test email.<br><img src="cid:image"> <br>Thanks!.', 'html')
msg.attach(body)
fp = open('C:/Users/renan.p.costa/img.png', 'rb')
image = MIMEImage(fp.read())
fp.close()
image.add_header('Content-ID', '<image>')
msg.attach(image)
file='C:/Users/renan.p.costa/file.xlsx'
_filename='file.xlsx'
fp=open(file,'rb')
excelfile = email.mime.application.MIMEApplication(fp.read(),_subtype="xlsx")
fp.close()
anexo.add_header('Content-Disposition','attachment',filename=_filename)
msg.attach(excelfile)
s = smtplib.SMTP('smtp-mail.outlook.com', 587)
s.ehlo()
s.starttls()
s.login(_from,_pass)
s.sendmail(msg['From'],msg['To'], msg.as_string())
s.quit()
python
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
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Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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My python code send a e-mail from my work aaddress to my gmail address, but they not send to any outlook address or work address.
When I send the email it appears in the sent box, regardless of whether it was delivered or not.
import smtplib
import mimetypes
import email
import email.mime.application
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
_from = 'myaddress@work.com.br'
_pass = 'pass'
_to = ['mygmail@gmail.com','myaddress@work.com.br']
msg = email.mime.multipart.MIMEMultipart()
msg['Subject'] = 'Test'
msg['From'] = 'myaddress@work.com.br'
msg['To'] = ", ".join(_to)
body = MIMEText('Hi, this is a test email.<br><img src="cid:image"> <br>Thanks!.', 'html')
msg.attach(body)
fp = open('C:/Users/renan.p.costa/img.png', 'rb')
image = MIMEImage(fp.read())
fp.close()
image.add_header('Content-ID', '<image>')
msg.attach(image)
file='C:/Users/renan.p.costa/file.xlsx'
_filename='file.xlsx'
fp=open(file,'rb')
excelfile = email.mime.application.MIMEApplication(fp.read(),_subtype="xlsx")
fp.close()
anexo.add_header('Content-Disposition','attachment',filename=_filename)
msg.attach(excelfile)
s = smtplib.SMTP('smtp-mail.outlook.com', 587)
s.ehlo()
s.starttls()
s.login(_from,_pass)
s.sendmail(msg['From'],msg['To'], msg.as_string())
s.quit()
python
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
My python code send a e-mail from my work aaddress to my gmail address, but they not send to any outlook address or work address.
When I send the email it appears in the sent box, regardless of whether it was delivered or not.
import smtplib
import mimetypes
import email
import email.mime.application
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
_from = 'myaddress@work.com.br'
_pass = 'pass'
_to = ['mygmail@gmail.com','myaddress@work.com.br']
msg = email.mime.multipart.MIMEMultipart()
msg['Subject'] = 'Test'
msg['From'] = 'myaddress@work.com.br'
msg['To'] = ", ".join(_to)
body = MIMEText('Hi, this is a test email.<br><img src="cid:image"> <br>Thanks!.', 'html')
msg.attach(body)
fp = open('C:/Users/renan.p.costa/img.png', 'rb')
image = MIMEImage(fp.read())
fp.close()
image.add_header('Content-ID', '<image>')
msg.attach(image)
file='C:/Users/renan.p.costa/file.xlsx'
_filename='file.xlsx'
fp=open(file,'rb')
excelfile = email.mime.application.MIMEApplication(fp.read(),_subtype="xlsx")
fp.close()
anexo.add_header('Content-Disposition','attachment',filename=_filename)
msg.attach(excelfile)
s = smtplib.SMTP('smtp-mail.outlook.com', 587)
s.ehlo()
s.starttls()
s.login(_from,_pass)
s.sendmail(msg['From'],msg['To'], msg.as_string())
s.quit()
python
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
My python code send a e-mail from my work aaddress to my gmail address, but they not send to any outlook address or work address.
When I send the email it appears in the sent box, regardless of whether it was delivered or not.
import smtplib
import mimetypes
import email
import email.mime.application
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
_from = 'myaddress@work.com.br'
_pass = 'pass'
_to = ['mygmail@gmail.com','myaddress@work.com.br']
msg = email.mime.multipart.MIMEMultipart()
msg['Subject'] = 'Test'
msg['From'] = 'myaddress@work.com.br'
msg['To'] = ", ".join(_to)
body = MIMEText('Hi, this is a test email.<br><img src="cid:image"> <br>Thanks!.', 'html')
msg.attach(body)
fp = open('C:/Users/renan.p.costa/img.png', 'rb')
image = MIMEImage(fp.read())
fp.close()
image.add_header('Content-ID', '<image>')
msg.attach(image)
file='C:/Users/renan.p.costa/file.xlsx'
_filename='file.xlsx'
fp=open(file,'rb')
excelfile = email.mime.application.MIMEApplication(fp.read(),_subtype="xlsx")
fp.close()
anexo.add_header('Content-Disposition','attachment',filename=_filename)
msg.attach(excelfile)
s = smtplib.SMTP('smtp-mail.outlook.com', 587)
s.ehlo()
s.starttls()
s.login(_from,_pass)
s.sendmail(msg['From'],msg['To'], msg.as_string())
s.quit()
python
python
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
asked Jan 18 at 12:32
Renan da CostaRenan da Costa
82
82
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Renan da Costa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try to send a list of emails (_to) instead of a string of emails separated by , so you need a list of to-address strings (a bare string will be treated as a list with 1 address).
In your code, you can modify the line:
s.sendmail(msg['From'],msg['To'], msg.as_string())
by this other one:
s.sendmail(msg['From'],_to, msg.as_string())
EDIT
If it doesn't work, you can try iterating the list, so you make diferent sendmails for every email in the list:
for to_email in _to:
s.sendmail(msg['From'],to_email, msg.as_string())
answered Jan 18 at 12:42
nachonacho
2,62011223
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try to send a list of emails (_to) instead of a string of emails separated by , so you need a list of to-address strings (a bare string will be treated as a list with 1 address).
In your code, you can modify the line:
s.sendmail(msg['From'],msg['To'], msg.as_string())
by this other one:
s.sendmail(msg['From'],_to, msg.as_string())
EDIT
If it doesn't work, you can try iterating the list, so you make diferent sendmails for every email in the list:
for to_email in _to:
s.sendmail(msg['From'],to_email, msg.as_string())
answered Jan 18 at 12:42
nachonacho
2,62011223
add a comment |
Try to send a list of emails (_to) instead of a string of emails separated by , so you need a list of to-address strings (a bare string will be treated as a list with 1 address).
In your code, you can modify the line:
s.sendmail(msg['From'],msg['To'], msg.as_string())
by this other one:
s.sendmail(msg['From'],_to, msg.as_string())
EDIT
If it doesn't work, you can try iterating the list, so you make diferent sendmails for every email in the list:
for to_email in _to:
s.sendmail(msg['From'],to_email, msg.as_string())
answered Jan 18 at 12:42
nachonacho
2,62011223
add a comment |
Try to send a list of emails (_to) instead of a string of emails separated by , so you need a list of to-address strings (a bare string will be treated as a list with 1 address).
In your code, you can modify the line:
s.sendmail(msg['From'],msg['To'], msg.as_string())
by this other one:
s.sendmail(msg['From'],_to, msg.as_string())
EDIT
If it doesn't work, you can try iterating the list, so you make diferent sendmails for every email in the list:
for to_email in _to:
s.sendmail(msg['From'],to_email, msg.as_string())
answered Jan 18 at 12:42
nachonacho
2,62011223
Try to send a list of emails (_to) instead of a string of emails separated by , so you need a list of to-address strings (a bare string will be treated as a list with 1 address).
In your code, you can modify the line:
s.sendmail(msg['From'],msg['To'], msg.as_string())
by this other one:
s.sendmail(msg['From'],_to, msg.as_string())
EDIT
If it doesn't work, you can try iterating the list, so you make diferent sendmails for every email in the list:
for to_email in _to:
s.sendmail(msg['From'],to_email, msg.as_string())
answered Jan 18 at 12:42
nachonacho
2,62011223
edited Jan 18 at 13:16
answered Jan 18 at 12:42
nachonacho
2,62011223
answered Jan 18 at 12:42
nachonacho
2,62011223
answered Jan 18 at 12:42
nachonacho
2,62011223
2,62011223
add a comment |
add a comment |
Renan da Costa is a new contributor. Be nice, and check out our Code of Conduct.
Renan da Costa is a new contributor. Be nice, and check out our Code of Conduct.
Renan da Costa is a new contributor. Be nice, and check out our Code of Conduct.
Renan da Costa is a new contributor. Be nice, and check out our Code of Conduct.
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