Brtdku

The most easy way to open a file with the default application is:

System.Diagnostics.Process.Start(@"c:myPDF.pdf");

However, I would like to know if exists a way to set parameters to the default application, because I would like to open a pdf in a determinate page number.

I know how can I do it creating a new process and set the parameters, but in this way I need to indicate the path of the application, and I would like to have a portable application and not to have to set the path of the applications each time I use the application in other computer. My idea is that I expect that the computer has installed the pdf reader and only say what page open.

Thanks.

EDIT (thanks to surfbutler comment in the question comments)
If you want the file to be opened with the default application, I mean without specifying Acrobat or Reader, you can't open the file in the specified page.

On the other hand, if you are Ok with specifying Acrobat or Reader, keep reading:

You can do it without telling the full Acrobat path, like this:

Process myProcess = new Process();    

myProcess.StartInfo.FileName = "acroRd32.exe"; //not the full application path

myProcess.StartInfo.Arguments = "/A "page=2=OpenActions" C:\example.pdf";

myProcess.Start();

If you don't want the pdf to open with Reader but with Acrobat, chage the second line like this:

myProcess.StartInfo.FileName = "Acrobat.exe";

SECOND EDIT: Finding the default application for the pdf extension

You can query the registry to identify the default application to open pdf files and then define FileName on your process's StartInfo accordingly. Again, thanks surfbutler for your comment :)

Follow this question for details on doing that: Finding the default application for opening a particular file type on Windows

I converted the VB code in the blog post linked by xsl to C# and modified it a bit:

public static bool TryGetRegisteredApplication(

                     string extension, out string registeredApp)

{

    string extensionId = GetClassesRootKeyDefaultValue(extension);

    if (extensionId == null)

    {

        registeredApp = null;

        return false;

    }



    string openCommand = GetClassesRootKeyDefaultValue(

            Path.Combine(new {extensionId, "shell", "open", "command"}));



    if (openCommand == null)

    {

        registeredApp = null;

        return false;

    }



    registeredApp = openCommand

                     .Replace("%1", string.Empty)

                     .Replace(""", string.Empty)

                     .Trim();

    return true;

}



private static string GetClassesRootKeyDefaultValue(string keyPath)

{

    using (var key = Registry.ClassesRoot.OpenSubKey(keyPath))

    {

        if (key == null)

        {

            return null;

        }



        var defaultValue = key.GetValue(null);

        if (defaultValue == null)

        {

            return null;

        }



        return defaultValue.ToString();

    }

}

EDIT - this is unreliable. See Finding the default application for opening a particular file type on Windows.

you can try with

Process process = new Process();

process.StartInfo.FileName = "yourProgram.exe";

process.StartInfo.Arguments = ..... //your parameters

process.Start();

this should be close!

public static void OpenWithDefaultProgram(string path)

{

    Process fileopener = new Process();

    fileopener.StartInfo.FileName = "explorer";

    fileopener.StartInfo.Arguments = """ + path + """;

    fileopener.Start();

}

Please add Settings under Properties for the Project and make use of them this way you have clean and easy configurable settings that can be configured as default

How To: Create a New Setting at Design Time

Update: after comments below

1. Right + Click on project


2. Add New Item


3. Under Visual C# Items -> General


4. Select Settings File