EOFError, even after trying the try and except block

Could anyone please state the reason why it is showing. I acknowledge it as python after reading the input states that there is nothing to read.

Python 3.6

    #!/bin/python3



import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        return

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

the error statement

Traceback (most recent call last):

  File "solution.py", line 27, in <module>

    N = int(input())

EOFError: EOF when reading a line

Blockquote

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

How are you testing this? What were you entering in the terminal prompt as int inputs and then to stop the input() (ex. Ctrl+C?)? I can't reproduce because if I use Ctrl+C to stop the input() I get the KeyboardInterrupt error, not the EOFError.

– Gino Mempin
Jan 21 at 0:15

1

The return line looks strange... Where's the function?

– iBug
Jan 22 at 5:24

Hi @GinoMempin, Testing is done itself in the code given by the website editor as stub code. Regarding this, the input is stdin and in the same way stdout. [hackerrank.com/challenges/30-conditional-statements/problem] . Thanks

– Vaitesh Selvaraj
Jan 22 at 5:25

@iBug, I too had the same intriguing question before trying the return. But a fellow [stackoverflow.com/a/42891677/10255905] had answered to similar question to use return to make it return nothing when EOF exception error comes.

– Vaitesh Selvaraj
Jan 22 at 5:31

1

+1 @GinoMempin, Well mate!! it did worked. initially i thought not to mess with the stub code as they have to test the code i have coded inside. but it turns out that it was indeed a function.

– Vaitesh Selvaraj
Jan 22 at 8:38

|
show 2 more comments

Could anyone please state the reason why it is showing. I acknowledge it as python after reading the input states that there is nothing to read.

Python 3.6

    #!/bin/python3



import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        return

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

the error statement

Traceback (most recent call last):

  File "solution.py", line 27, in <module>

    N = int(input())

EOFError: EOF when reading a line

Blockquote

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

How are you testing this? What were you entering in the terminal prompt as int inputs and then to stop the input() (ex. Ctrl+C?)? I can't reproduce because if I use Ctrl+C to stop the input() I get the KeyboardInterrupt error, not the EOFError.

– Gino Mempin
Jan 21 at 0:15

1

The return line looks strange... Where's the function?

– iBug
Jan 22 at 5:24

Hi @GinoMempin, Testing is done itself in the code given by the website editor as stub code. Regarding this, the input is stdin and in the same way stdout. [hackerrank.com/challenges/30-conditional-statements/problem] . Thanks

– Vaitesh Selvaraj
Jan 22 at 5:25

@iBug, I too had the same intriguing question before trying the return. But a fellow [stackoverflow.com/a/42891677/10255905] had answered to similar question to use return to make it return nothing when EOF exception error comes.

– Vaitesh Selvaraj
Jan 22 at 5:31

1

+1 @GinoMempin, Well mate!! it did worked. initially i thought not to mess with the stub code as they have to test the code i have coded inside. but it turns out that it was indeed a function.

– Vaitesh Selvaraj
Jan 22 at 8:38

|
show 2 more comments

Could anyone please state the reason why it is showing. I acknowledge it as python after reading the input states that there is nothing to read.

Python 3.6

    #!/bin/python3



import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        return

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

the error statement

Traceback (most recent call last):

  File "solution.py", line 27, in <module>

    N = int(input())

EOFError: EOF when reading a line

Blockquote

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

Could anyone please state the reason why it is showing. I acknowledge it as python after reading the input states that there is nothing to read.

Python 3.6

    #!/bin/python3



import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        return

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

the error statement

Traceback (most recent call last):

  File "solution.py", line 27, in <module>

    N = int(input())

EOFError: EOF when reading a line

Blockquote

python-3.x eoferror

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

edited Jan 22 at 5:19

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

asked Jan 20 at 9:46

Vaitesh Selvaraj

104

How are you testing this? What were you entering in the terminal prompt as int inputs and then to stop the input() (ex. Ctrl+C?)? I can't reproduce because if I use Ctrl+C to stop the input() I get the KeyboardInterrupt error, not the EOFError.

– Gino Mempin
Jan 21 at 0:15

1

The return line looks strange... Where's the function?

– iBug
Jan 22 at 5:24

Hi @GinoMempin, Testing is done itself in the code given by the website editor as stub code. Regarding this, the input is stdin and in the same way stdout. [hackerrank.com/challenges/30-conditional-statements/problem] . Thanks

– Vaitesh Selvaraj
Jan 22 at 5:25

@iBug, I too had the same intriguing question before trying the return. But a fellow [stackoverflow.com/a/42891677/10255905] had answered to similar question to use return to make it return nothing when EOF exception error comes.

– Vaitesh Selvaraj
Jan 22 at 5:31

1

+1 @GinoMempin, Well mate!! it did worked. initially i thought not to mess with the stub code as they have to test the code i have coded inside. but it turns out that it was indeed a function.

– Vaitesh Selvaraj
Jan 22 at 8:38

|
show 2 more comments

How are you testing this? What were you entering in the terminal prompt as int inputs and then to stop the input() (ex. Ctrl+C?)? I can't reproduce because if I use Ctrl+C to stop the input() I get the KeyboardInterrupt error, not the EOFError.

– Gino Mempin
Jan 21 at 0:15

1

The return line looks strange... Where's the function?

– iBug
Jan 22 at 5:24

Hi @GinoMempin, Testing is done itself in the code given by the website editor as stub code. Regarding this, the input is stdin and in the same way stdout. [hackerrank.com/challenges/30-conditional-statements/problem] . Thanks

– Vaitesh Selvaraj
Jan 22 at 5:25

@iBug, I too had the same intriguing question before trying the return. But a fellow [stackoverflow.com/a/42891677/10255905] had answered to similar question to use return to make it return nothing when EOF exception error comes.

– Vaitesh Selvaraj
Jan 22 at 5:31

1

+1 @GinoMempin, Well mate!! it did worked. initially i thought not to mess with the stub code as they have to test the code i have coded inside. but it turns out that it was indeed a function.

– Vaitesh Selvaraj
Jan 22 at 8:38

How are you testing this? What were you entering in the terminal prompt as int inputs and then to stop the input() (ex. Ctrl+C?)? I can't reproduce because if I use Ctrl+C to stop the input() I get the KeyboardInterrupt error, not the EOFError.

– Gino Mempin
Jan 21 at 0:15

The return line looks strange... Where's the function?

– iBug
Jan 22 at 5:24

Hi @GinoMempin, Testing is done itself in the code given by the website editor as stub code. Regarding this, the input is stdin and in the same way stdout. [hackerrank.com/challenges/30-conditional-statements/problem] . Thanks

– Vaitesh Selvaraj
Jan 22 at 5:25

@iBug, I too had the same intriguing question before trying the return. But a fellow [stackoverflow.com/a/42891677/10255905] had answered to similar question to use return to make it return nothing when EOF exception error comes.

– Vaitesh Selvaraj
Jan 22 at 5:31

+1 @GinoMempin, Well mate!! it did worked. initially i thought not to mess with the stub code as they have to test the code i have coded inside. but it turns out that it was indeed a function.

– Vaitesh Selvaraj
Jan 22 at 8:38

|
show 2 more comments

1 Answer
1

active

oldest

votes

return only works when you are inside a function and you want to exit from that function. In this case you just want to terminate your while loop so your should use break keyword.

Also in given question, you just need to read a single integer (I guess you are working on something different?)

import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        break

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

answered Jan 22 at 5:34

unlut

891310

add a comment |

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1 Answer
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oldest

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1 Answer
1

active

oldest

votes

return only works when you are inside a function and you want to exit from that function. In this case you just want to terminate your while loop so your should use break keyword.

Also in given question, you just need to read a single integer (I guess you are working on something different?)

import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        break

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

answered Jan 22 at 5:34

unlut

891310

add a comment |

return only works when you are inside a function and you want to exit from that function. In this case you just want to terminate your while loop so your should use break keyword.

Also in given question, you just need to read a single integer (I guess you are working on something different?)

import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        break

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

answered Jan 22 at 5:34

unlut

891310

add a comment |

return only works when you are inside a function and you want to exit from that function. In this case you just want to terminate your while loop so your should use break keyword.

Also in given question, you just need to read a single integer (I guess you are working on something different?)

import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        break

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

answered Jan 22 at 5:34

unlut

891310

return only works when you are inside a function and you want to exit from that function. In this case you just want to terminate your while loop so your should use break keyword.

Also in given question, you just need to read a single integer (I guess you are working on something different?)

import math

import os

import random

import re

import sys



while True:

    try:

        N = int(input())

    except EOFError:

        break

#N = int(input())





if N % 2 != 0:

    print("Wierd")

elif N % 2 == 0 and N in range(2, 6):

    print("Not Wierd")

elif N % 2 == 0 and N in range(6, 21):

    print("Wierd")

elif N % 2 == 0 and N > 20:

    print("Wierd")







if __name__ == '__main__':

    N = int(input())

answered Jan 22 at 5:34

unlut

891310

answered Jan 22 at 5:34

unlut

891310

answered Jan 22 at 5:34

unlut

891310

answered Jan 22 at 5:34

unlut

891310

add a comment |

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