How do I convert characters to a time that has fractional seconds without adding a date?
Multi tool use
Is there a way to convert a string of characters to a time that retains the fractional seconds, but does not add a date to the data?
Background: Data that I saved overnight (starting at 22:00 and ending at 06:00) is recorded with a time, but not a date.
I would like to be able to perform something like an "if" statement on the times (i.e. if (time < midnight) date = yesterday.... else date = today)
I don't want to use something like strptime, because strptime adds today's date to the data:
> options(digits.secs=3)
> strptime("22:59:54.807", format="%H:%M:%OS")
[1] "2019-01-20 22:59:54.807 AEDT"
When I use times from the chron package, the fractional seconds are dropped:
> options(digits.secs=3)
> times("22:59:54.807")
[1] 22:59:55
r
asked Jan 19 at 20:54
talikarngtalikarng
1
add a comment |
Is there a way to convert a string of characters to a time that retains the fractional seconds, but does not add a date to the data?
Background: Data that I saved overnight (starting at 22:00 and ending at 06:00) is recorded with a time, but not a date.
I would like to be able to perform something like an "if" statement on the times (i.e. if (time < midnight) date = yesterday.... else date = today)
I don't want to use something like strptime, because strptime adds today's date to the data:
> options(digits.secs=3)
> strptime("22:59:54.807", format="%H:%M:%OS")
[1] "2019-01-20 22:59:54.807 AEDT"
When I use times from the chron package, the fractional seconds are dropped:
> options(digits.secs=3)
> times("22:59:54.807")
[1] 22:59:55
r
asked Jan 19 at 20:54
talikarngtalikarng
1
lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18
add a comment |
Is there a way to convert a string of characters to a time that retains the fractional seconds, but does not add a date to the data?
Background: Data that I saved overnight (starting at 22:00 and ending at 06:00) is recorded with a time, but not a date.
I would like to be able to perform something like an "if" statement on the times (i.e. if (time < midnight) date = yesterday.... else date = today)
I don't want to use something like strptime, because strptime adds today's date to the data:
> options(digits.secs=3)
> strptime("22:59:54.807", format="%H:%M:%OS")
[1] "2019-01-20 22:59:54.807 AEDT"
When I use times from the chron package, the fractional seconds are dropped:
> options(digits.secs=3)
> times("22:59:54.807")
[1] 22:59:55
r
asked Jan 19 at 20:54
talikarngtalikarng
1
Is there a way to convert a string of characters to a time that retains the fractional seconds, but does not add a date to the data?
Background: Data that I saved overnight (starting at 22:00 and ending at 06:00) is recorded with a time, but not a date.
I would like to be able to perform something like an "if" statement on the times (i.e. if (time < midnight) date = yesterday.... else date = today)
I don't want to use something like strptime, because strptime adds today's date to the data:
> options(digits.secs=3)
> strptime("22:59:54.807", format="%H:%M:%OS")
[1] "2019-01-20 22:59:54.807 AEDT"
When I use times from the chron package, the fractional seconds are dropped:
> options(digits.secs=3)
> times("22:59:54.807")
[1] 22:59:55
r
r
asked Jan 19 at 20:54
talikarngtalikarng
1
asked Jan 19 at 20:54
talikarngtalikarng
1
asked Jan 19 at 20:54
talikarngtalikarng
1
asked Jan 19 at 20:54
talikarngtalikarng
1
asked Jan 19 at 20:54
talikarngtalikarng
1
1
lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18
add a comment |
lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18
lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18
lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18
add a comment |
1 Answer
1
active
oldest
votes
Using base::strftime(), you can obtain a character of the desired time to any divide of seconds you want. Below I have saved the current time to unit 1/1000 of a second, using the number "4" after "OS":
Using current system time:
time = Sys.time()
str(time)
POSIXct[1:1], format: "2019-01-19 15:41:28.185"
newTime = strftime(Sys.time(), format="%H:%M:%OS4")
str(newTime)
chr "15:41:28.1851"
newTime
[1] "15:41:28.1851"
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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oldest
votes
active
oldest
votes
Using base::strftime(), you can obtain a character of the desired time to any divide of seconds you want. Below I have saved the current time to unit 1/1000 of a second, using the number "4" after "OS":
Using current system time:
time = Sys.time()
str(time)
POSIXct[1:1], format: "2019-01-19 15:41:28.185"
newTime = strftime(Sys.time(), format="%H:%M:%OS4")
str(newTime)
chr "15:41:28.1851"
newTime
[1] "15:41:28.1851"
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
add a comment |
Using base::strftime(), you can obtain a character of the desired time to any divide of seconds you want. Below I have saved the current time to unit 1/1000 of a second, using the number "4" after "OS":
Using current system time:
time = Sys.time()
str(time)
POSIXct[1:1], format: "2019-01-19 15:41:28.185"
newTime = strftime(Sys.time(), format="%H:%M:%OS4")
str(newTime)
chr "15:41:28.1851"
newTime
[1] "15:41:28.1851"
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
add a comment |
Using base::strftime(), you can obtain a character of the desired time to any divide of seconds you want. Below I have saved the current time to unit 1/1000 of a second, using the number "4" after "OS":
Using current system time:
time = Sys.time()
str(time)
POSIXct[1:1], format: "2019-01-19 15:41:28.185"
newTime = strftime(Sys.time(), format="%H:%M:%OS4")
str(newTime)
chr "15:41:28.1851"
newTime
[1] "15:41:28.1851"
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
Using base::strftime(), you can obtain a character of the desired time to any divide of seconds you want. Below I have saved the current time to unit 1/1000 of a second, using the number "4" after "OS":
Using current system time:
time = Sys.time()
str(time)
POSIXct[1:1], format: "2019-01-19 15:41:28.185"
newTime = strftime(Sys.time(), format="%H:%M:%OS4")
str(newTime)
chr "15:41:28.1851"
newTime
[1] "15:41:28.1851"
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
edited Jan 19 at 21:50
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
answered Jan 19 at 21:37
Jessica BurnettJessica Burnett
115
115
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
add a comment |
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
Thanks @JessicaBurnett, once I have the 'chr "15:41:28.1851"', how do you convert that back to a "time" that can be used in a conditional statement such as an "if" statement?
– talikarng
Jan 19 at 23:27
add a comment |
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lubridate package in R is your best bet!
– Data Science
Jan 19 at 21:18