unary operator expected with integerrs and arrays












0















So I wrote the following code :



#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

        echo ${names[$a]}

        a=`expr a + 1`

done


And get the following Error, And I have no idea why it didn't work.
The first name is printed, and the others are not.



for loop

fulmetall

expr: non-integer argument

./for_loop.sh: line 8: [: -lt: unary operator expected





arrays bash unix







share|improve this question


















  • 4





    Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

    – PesaThe
    Jan 19 at 21:18


















0















So I wrote the following code :



#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

        echo ${names[$a]}

        a=`expr a + 1`

done


And get the following Error, And I have no idea why it didn't work.
The first name is printed, and the others are not.



for loop

fulmetall

expr: non-integer argument

./for_loop.sh: line 8: [: -lt: unary operator expected





arrays bash unix







share|improve this question


















  • 4





    Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

    – PesaThe
    Jan 19 at 21:18
















0












0








0








So I wrote the following code :



#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

        echo ${names[$a]}

        a=`expr a + 1`

done


And get the following Error, And I have no idea why it didn't work.
The first name is printed, and the others are not.



for loop

fulmetall

expr: non-integer argument

./for_loop.sh: line 8: [: -lt: unary operator expected





arrays bash unix







share|improve this question














So I wrote the following code :



#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

        echo ${names[$a]}

        a=`expr a + 1`

done


And get the following Error, And I have no idea why it didn't work.
The first name is printed, and the others are not.



for loop

fulmetall

expr: non-integer argument

./for_loop.sh: line 8: [: -lt: unary operator expected





arrays bash unix




arrays bash unix






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 19 at 21:11









ablil98ablil98

536




536








  • 4





    Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

    – PesaThe
    Jan 19 at 21:18
















  • 4





    Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

    – PesaThe
    Jan 19 at 21:18










4




4





Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

– PesaThe
Jan 19 at 21:18







Use expr $a... instead of just a or save yourself some future trouble and use arithmetic expansion: ((a++)) or a=$((a+1)).

– PesaThe
Jan 19 at 21:18














1 Answer
1






active

oldest

votes


















1














#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

    echo ${names[$a]}

    a=`expr $a + 1`

done





share|improve this answer
























  • thank you it worked

    – ablil98
    Jan 19 at 21:21











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1














#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

    echo ${names[$a]}

    a=`expr $a + 1`

done





share|improve this answer
























  • thank you it worked

    – ablil98
    Jan 19 at 21:21
















1














#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

    echo ${names[$a]}

    a=`expr $a + 1`

done





share|improve this answer
























  • thank you it worked

    – ablil98
    Jan 19 at 21:21














1












1








1







#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

    echo ${names[$a]}

    a=`expr $a + 1`

done





share|improve this answer













#!/bin/bash



echo "for loop"



names=("fulmetall" "alphonse" "flame alchemesit" "king bradely" "hoenheim")



a=0

while [ $a -lt 5 ];

do

    echo ${names[$a]}

    a=`expr $a + 1`

done






share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 19 at 21:18









TDKTDK

748218




748218













  • thank you it worked

    – ablil98
    Jan 19 at 21:21



















  • thank you it worked

    – ablil98
    Jan 19 at 21:21

















thank you it worked

– ablil98
Jan 19 at 21:21





thank you it worked

– ablil98
Jan 19 at 21:21


















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