The $.when.done() is never called after ajax calls are done
I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.
const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}
const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');
$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}
jquery ajax promise
edited Jan 20 at 12:44
20yco
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
add a comment |
I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.
const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}
const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');
$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}
jquery ajax promise
edited Jan 20 at 12:44
20yco
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
1
Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20
add a comment |
I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.
const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}
const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');
$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}
jquery ajax promise
edited Jan 20 at 12:44
20yco
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.
const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}
const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');
$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}
jquery ajax promise
jquery ajax promise
edited Jan 20 at 12:44
20yco
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
edited Jan 20 at 12:44
20yco
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
edited Jan 20 at 12:44
20yco
703419
edited Jan 20 at 12:44
20yco
703419
edited Jan 20 at 12:44
20yco
703419
703419
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
asked Jan 20 at 7:11
Ivanhoe CheungIvanhoe Cheung
815
815
1
Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20
add a comment |
1
Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20
1
1
Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20
Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20
add a comment |
1 Answer
1
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oldest
votes
I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
add a comment |
I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
add a comment |
I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
answered Jan 20 at 11:04
Ivanhoe CheungIvanhoe Cheung
815
815
add a comment |
add a comment |
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Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)
– CertainPerformance
Jan 20 at 7:20