The $.when.done() is never called after ajax calls are done

Multi tool use
Multi tool use












-1















I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.



const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}

const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');

$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}









share|improve this question




















  • 1





    Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

    – CertainPerformance
    Jan 20 at 7:20
















-1















I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.



const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}

const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');

$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}









share|improve this question




















  • 1





    Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

    – CertainPerformance
    Jan 20 at 7:20














-1












-1








-1








I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.



const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}

const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');

$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}









share|improve this question
















I would like to print foobar after all 5 ajax calls are done. It means even 4 of them are loaded but 1 of them is still loading, the "foobar" won't be printed yet. I tried many solutions online but still can't print foobar after all ajax calls are done.



const ajaxCall = (prop, url) => {
return $.ajax({
type: "GET",
url: url,
timeout: 18000000,
success: function (data) {
console.log(data);
db[prop] = JSON.parse(data);
},
error: function (error) {
console.log('ajax error');
}
});
}

const loadData = () => {
let request_1 = ajaxCall('prop1','http://' + host + ':' + port + '/' + workspace + '/api/1.php');
let request_2 = ajaxCall('prop2','http://' + host + ':' + port + '/' + workspace + '/api/2.php');
let request_3 = ajaxCall('prop3','http://' + host + ':' + port + '/' + workspace + '/api/3.php');
let request_4 = ajaxCall('prop4','http://' + host + ':' + port + '/' + workspace + '/api/4.php');
let request_5 = ajaxCall('prop5','http://' + host + ':' + port + '/' + workspace + '/api/5.php');

$.when(request_1,request_2, request_3, request_4, request_5)
.done(() => {
console.log('foobar');
})
}






jquery ajax promise






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edited Jan 20 at 12:44









20yco

703419




703419










asked Jan 20 at 7:11









Ivanhoe CheungIvanhoe Cheung

815




815








  • 1





    Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

    – CertainPerformance
    Jan 20 at 7:20














  • 1





    Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

    – CertainPerformance
    Jan 20 at 7:20








1




1





Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

– CertainPerformance
Jan 20 at 7:20





Code seems fine to me jsfiddle.net/knbtgod8 The problem is elsewhere, check that no errors are thrown (look at network tab)

– CertainPerformance
Jan 20 at 7:20












1 Answer
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I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".






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    1 Answer
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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes









    -1














    I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".






    share|improve this answer




























      -1














      I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".






      share|improve this answer


























        -1












        -1








        -1







        I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".






        share|improve this answer













        I just found my code actually does work. The problem is caused by the DB connection issue. The DB is not connected properly but still the AJAX response it as "done".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 20 at 11:04









        Ivanhoe CheungIvanhoe Cheung

        815




        815
































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