FileNotFoundError: [Errno 2] No such file or directory: 'englishcomputers.yml'

-1

for files in os.listdir('english'):

data=open('english'+ files,'r').readlines()

bot.train(data)

The first line of the for loop which opens the file produces an error.

I changed "computers.yml" file also but its not working as it seems like it didn't get the path correctly.

Any solution for this please?

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

2

How about giving the right path? What is it, that is not understandable in the error message?

– Andronicus
Jan 20 at 7:14

Your code is not indented it seems? Also try giving the full file name. Complete Stacktrace should also be posted.

– Ashu Grover
Jan 20 at 7:19

def main(): chatbot = ChatBot('Bot', storage_adapter ='chatterbot.storage.SQLStorageAdapter', trainer = 'chatterbot.trainers.ListTrainer') for files in os.walk('hector/'): convData = open(r'hector/' + files, encoding='latin-1').readlines() #convData = open('hector/' + files, 'r').readlines() chatbot.set_trainer(ListTrainer) chatbot.train(convData)

– Janidu Jayasanka
Jan 29 at 11:05

add a comment |

-1

for files in os.listdir('english'):

data=open('english'+ files,'r').readlines()

bot.train(data)

The first line of the for loop which opens the file produces an error.

I changed "computers.yml" file also but its not working as it seems like it didn't get the path correctly.

Any solution for this please?

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

2

How about giving the right path? What is it, that is not understandable in the error message?

– Andronicus
Jan 20 at 7:14

Your code is not indented it seems? Also try giving the full file name. Complete Stacktrace should also be posted.

– Ashu Grover
Jan 20 at 7:19

def main(): chatbot = ChatBot('Bot', storage_adapter ='chatterbot.storage.SQLStorageAdapter', trainer = 'chatterbot.trainers.ListTrainer') for files in os.walk('hector/'): convData = open(r'hector/' + files, encoding='latin-1').readlines() #convData = open('hector/' + files, 'r').readlines() chatbot.set_trainer(ListTrainer) chatbot.train(convData)

– Janidu Jayasanka
Jan 29 at 11:05

add a comment |

-1

for files in os.listdir('english'):

data=open('english'+ files,'r').readlines()

bot.train(data)

The first line of the for loop which opens the file produces an error.

I changed "computers.yml" file also but its not working as it seems like it didn't get the path correctly.

Any solution for this please?

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

for files in os.listdir('english'):

data=open('english'+ files,'r').readlines()

bot.train(data)

The first line of the for loop which opens the file produces an error.

I changed "computers.yml" file also but its not working as it seems like it didn't get the path correctly.

Any solution for this please?

python filepath chatbot

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

edited Jan 20 at 8:16

Graham

3,612143659

edited Jan 20 at 8:16

Graham

3,612143659

edited Jan 20 at 8:16

Graham

3,612143659

asked Jan 20 at 7:07

Janidu Jayasanka

asked Jan 20 at 7:07

Janidu Jayasanka

asked Jan 20 at 7:07

Janidu Jayasanka

2

How about giving the right path? What is it, that is not understandable in the error message?

– Andronicus
Jan 20 at 7:14

Your code is not indented it seems? Also try giving the full file name. Complete Stacktrace should also be posted.

– Ashu Grover
Jan 20 at 7:19

def main(): chatbot = ChatBot('Bot', storage_adapter ='chatterbot.storage.SQLStorageAdapter', trainer = 'chatterbot.trainers.ListTrainer') for files in os.walk('hector/'): convData = open(r'hector/' + files, encoding='latin-1').readlines() #convData = open('hector/' + files, 'r').readlines() chatbot.set_trainer(ListTrainer) chatbot.train(convData)

– Janidu Jayasanka
Jan 29 at 11:05

add a comment |

2

How about giving the right path? What is it, that is not understandable in the error message?

– Andronicus
Jan 20 at 7:14

Your code is not indented it seems? Also try giving the full file name. Complete Stacktrace should also be posted.

– Ashu Grover
Jan 20 at 7:19

def main(): chatbot = ChatBot('Bot', storage_adapter ='chatterbot.storage.SQLStorageAdapter', trainer = 'chatterbot.trainers.ListTrainer') for files in os.walk('hector/'): convData = open(r'hector/' + files, encoding='latin-1').readlines() #convData = open('hector/' + files, 'r').readlines() chatbot.set_trainer(ListTrainer) chatbot.train(convData)

– Janidu Jayasanka
Jan 29 at 11:05

How about giving the right path? What is it, that is not understandable in the error message?

– Andronicus
Jan 20 at 7:14

Your code is not indented it seems? Also try giving the full file name. Complete Stacktrace should also be posted.

– Ashu Grover
Jan 20 at 7:19

def main(): chatbot = ChatBot('Bot', storage_adapter ='chatterbot.storage.SQLStorageAdapter', trainer = 'chatterbot.trainers.ListTrainer') for files in os.walk('hector/'): convData = open(r'hector/' + files, encoding='latin-1').readlines() #convData = open('hector/' + files, 'r').readlines() chatbot.set_trainer(ListTrainer) chatbot.train(convData)

– Janidu Jayasanka
Jan 29 at 11:05

add a comment |

1 Answer
1

active

oldest

votes

You need to include a / separating the directory and the file name in order to open the specific file from its appropriate path within the english directory.

#!/usr/bin/env python



import os



for files in os.listdir('english'):

    file_path=os.path.join('english',files)

    data=open(file_path,'r').readlines()

    bot.train(data)

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You need to include a / separating the directory and the file name in order to open the specific file from its appropriate path within the english directory.

#!/usr/bin/env python



import os



for files in os.listdir('english'):

    file_path=os.path.join('english',files)

    data=open(file_path,'r').readlines()

    bot.train(data)

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

add a comment |

You need to include a / separating the directory and the file name in order to open the specific file from its appropriate path within the english directory.

#!/usr/bin/env python



import os



for files in os.listdir('english'):

    file_path=os.path.join('english',files)

    data=open(file_path,'r').readlines()

    bot.train(data)

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

add a comment |

You need to include a / separating the directory and the file name in order to open the specific file from its appropriate path within the english directory.

#!/usr/bin/env python



import os



for files in os.listdir('english'):

    file_path=os.path.join('english',files)

    data=open(file_path,'r').readlines()

    bot.train(data)

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

You need to include a / separating the directory and the file name in order to open the specific file from its appropriate path within the english directory.

#!/usr/bin/env python



import os



for files in os.listdir('english'):

    file_path=os.path.join('english',files)

    data=open(file_path,'r').readlines()

    bot.train(data)

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

edited Jan 20 at 14:56

answered Jan 20 at 7:19

waymobetta

319112

answered Jan 20 at 7:19

waymobetta

319112

answered Jan 20 at 7:19

waymobetta

319112

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

add a comment |

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

What if code is executed on Windows? os.path.join would be more universal

– Sasha Tsukanov
Jan 20 at 9:32

Thanks @SashaTsukanov, good suggestion. I've updated my answer

– waymobetta
Jan 20 at 14:57

add a comment |

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