Trying to select the filepath without declaring it in string

-2

I'm trying to make it so when i click my button I can chose which .txt file i want to select and than get the Lines Count displayed on my label

string filePath = "C:\Users\Ristic\Desktop\Neki.txt";

int count = System.IO.File.ReadLines(filePath).Count();

string a = count.ToString();

label1.Text = a;

asked Jan 20 at 3:17

Marin Sozanj Sekovic

2

And what's a problem?

– Polly
Jan 20 at 3:22

add a comment |

-2

I'm trying to make it so when i click my button I can chose which .txt file i want to select and than get the Lines Count displayed on my label

string filePath = "C:\Users\Ristic\Desktop\Neki.txt";

int count = System.IO.File.ReadLines(filePath).Count();

string a = count.ToString();

label1.Text = a;

asked Jan 20 at 3:17

Marin Sozanj Sekovic

2

And what's a problem?

– Polly
Jan 20 at 3:22

add a comment |

-2

I'm trying to make it so when i click my button I can chose which .txt file i want to select and than get the Lines Count displayed on my label

string filePath = "C:\Users\Ristic\Desktop\Neki.txt";

int count = System.IO.File.ReadLines(filePath).Count();

string a = count.ToString();

label1.Text = a;

asked Jan 20 at 3:17

Marin Sozanj Sekovic

I'm trying to make it so when i click my button I can chose which .txt file i want to select and than get the Lines Count displayed on my label

string filePath = "C:\Users\Ristic\Desktop\Neki.txt";

int count = System.IO.File.ReadLines(filePath).Count();

string a = count.ToString();

label1.Text = a;

c# visual-studio-2017

asked Jan 20 at 3:17

Marin Sozanj Sekovic

asked Jan 20 at 3:17

Marin Sozanj Sekovic

asked Jan 20 at 3:17

Marin Sozanj Sekovic

asked Jan 20 at 3:17

Marin Sozanj Sekovic

asked Jan 20 at 3:17

Marin Sozanj Sekovic

2

And what's a problem?

– Polly
Jan 20 at 3:22

add a comment |

2

And what's a problem?

– Polly
Jan 20 at 3:22

And what's a problem?

– Polly
Jan 20 at 3:22

add a comment |

1 Answer
1

active

oldest

votes

You need to use OpenFileDialog here.

For example,

var openFileDialog1 = new OpenFileDialog()

{

    DefaultExt = "txt",  

    Filter = "txt files (*.txt)|*.txt",  

}

openFileDialog1.ShowDialog();

if (openFileDialog1.ShowDialog() == DialogResult.OK)  

{  

     filePath  = openFileDialog1.FileName;  

}

The OpenFileDialog.Filter property allows you to filter the files by extension, which in your case is ".txt".

You can read more on OpenFileDialog here

answered Jan 20 at 3:21

Anu Viswan

5,0482525

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You need to use OpenFileDialog here.

For example,

var openFileDialog1 = new OpenFileDialog()

{

    DefaultExt = "txt",  

    Filter = "txt files (*.txt)|*.txt",  

}

openFileDialog1.ShowDialog();

if (openFileDialog1.ShowDialog() == DialogResult.OK)  

{  

     filePath  = openFileDialog1.FileName;  

}

The OpenFileDialog.Filter property allows you to filter the files by extension, which in your case is ".txt".

You can read more on OpenFileDialog here

answered Jan 20 at 3:21

Anu Viswan

5,0482525

add a comment |

You need to use OpenFileDialog here.

For example,

var openFileDialog1 = new OpenFileDialog()

{

    DefaultExt = "txt",  

    Filter = "txt files (*.txt)|*.txt",  

}

openFileDialog1.ShowDialog();

if (openFileDialog1.ShowDialog() == DialogResult.OK)  

{  

     filePath  = openFileDialog1.FileName;  

}

The OpenFileDialog.Filter property allows you to filter the files by extension, which in your case is ".txt".

You can read more on OpenFileDialog here

answered Jan 20 at 3:21

Anu Viswan

5,0482525

add a comment |

You need to use OpenFileDialog here.

For example,

var openFileDialog1 = new OpenFileDialog()

{

    DefaultExt = "txt",  

    Filter = "txt files (*.txt)|*.txt",  

}

openFileDialog1.ShowDialog();

if (openFileDialog1.ShowDialog() == DialogResult.OK)  

{  

     filePath  = openFileDialog1.FileName;  

}

The OpenFileDialog.Filter property allows you to filter the files by extension, which in your case is ".txt".

You can read more on OpenFileDialog here

answered Jan 20 at 3:21

Anu Viswan

5,0482525

You need to use OpenFileDialog here.

For example,

var openFileDialog1 = new OpenFileDialog()

{

    DefaultExt = "txt",  

    Filter = "txt files (*.txt)|*.txt",  

}

openFileDialog1.ShowDialog();

if (openFileDialog1.ShowDialog() == DialogResult.OK)  

{  

     filePath  = openFileDialog1.FileName;  

}

The OpenFileDialog.Filter property allows you to filter the files by extension, which in your case is ".txt".

You can read more on OpenFileDialog here

answered Jan 20 at 3:21

Anu Viswan

5,0482525

answered Jan 20 at 3:21

Anu Viswan

5,0482525

answered Jan 20 at 3:21

Anu Viswan

5,0482525

answered Jan 20 at 3:21

Anu Viswan

5,0482525

add a comment |

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