Can someone tell me why string s in not printing in the following java program
-3
Can someone tell me why string s in not printing in the following java program.
import java.util.Scanner;
class Solution {
public static void main(String args) {
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
double d = scan.nextDouble();
String s = scan.nextLine();
// Write your code here.
System.out.println("String: " + s);
System.out.println("Double: " + d);
System.out.println("Int: " + i);
}
}
stdout stdin
edited Jan 20 at 16:41
Dev
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
add a comment |
-3
Can someone tell me why string s in not printing in the following java program.
import java.util.Scanner;
class Solution {
public static void main(String args) {
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
double d = scan.nextDouble();
String s = scan.nextLine();
// Write your code here.
System.out.println("String: " + s);
System.out.println("Double: " + d);
System.out.println("Int: " + i);
}
}
stdout stdin
edited Jan 20 at 16:41
Dev
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
for more information this read referencenextLine()method waiting for you to input on same line where you have not inputed anything it means it will print nothing
– Dev
Jan 20 at 14:20
add a comment |
-3
-3
-3
Can someone tell me why string s in not printing in the following java program.
import java.util.Scanner;
class Solution {
public static void main(String args) {
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
double d = scan.nextDouble();
String s = scan.nextLine();
// Write your code here.
System.out.println("String: " + s);
System.out.println("Double: " + d);
System.out.println("Int: " + i);
}
}
stdout stdin
edited Jan 20 at 16:41
Dev
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
Can someone tell me why string s in not printing in the following java program.
import java.util.Scanner;
class Solution {
public static void main(String args) {
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
double d = scan.nextDouble();
String s = scan.nextLine();
// Write your code here.
System.out.println("String: " + s);
System.out.println("Double: " + d);
System.out.println("Int: " + i);
}
}
stdout stdin
stdout stdin
edited Jan 20 at 16:41
Dev
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
edited Jan 20 at 16:41
Dev
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
edited Jan 20 at 16:41
Dev
637413
edited Jan 20 at 16:41
Dev
637413
edited Jan 20 at 16:41
Dev
637413
637413
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
asked Jan 20 at 14:08
iSarcastic99iSarcastic99
11
11
for more information this read referencenextLine()method waiting for you to input on same line where you have not inputed anything it means it will print nothing
– Dev
Jan 20 at 14:20
add a comment |
for more information this read referencenextLine()method waiting for you to input on same line where you have not inputed anything it means it will print nothing
– Dev
Jan 20 at 14:20
for more information this read reference
nextLine() method waiting for you to input on same line where you have not inputed anything it means it will print nothing– Dev
Jan 20 at 14:20
for more information this read reference
nextLine() method waiting for you to input on same line where you have not inputed anything it means it will print nothing– Dev
Jan 20 at 14:20
add a comment |
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for more information this read reference
nextLine()method waiting for you to input on same line where you have not inputed anything it means it will print nothing– Dev
Jan 20 at 14:20