Zapier gives error: `'unicode' object has no attribute 'copy'` for Python script
1
The script is simple:
import datetime
import json
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return json.dumps({'date': str(next_third_thursday)})
How do I get this code to run? What's the issue here?
python json python-2.7 datetime zapier
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
add a comment |
1
The script is simple:
import datetime
import json
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return json.dumps({'date': str(next_third_thursday)})
How do I get this code to run? What's the issue here?
python json python-2.7 datetime zapier
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
add a comment |
1
1
1
The script is simple:
import datetime
import json
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return json.dumps({'date': str(next_third_thursday)})
How do I get this code to run? What's the issue here?
python json python-2.7 datetime zapier
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
The script is simple:
import datetime
import json
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return json.dumps({'date': str(next_third_thursday)})
How do I get this code to run? What's the issue here?
python json python-2.7 datetime zapier
python json python-2.7 datetime zapier
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
edited Jan 20 at 16:45
Evan Cory Levine
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
asked Jan 20 at 14:29
Evan Cory LevineEvan Cory Levine
257
257
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
Zapier expects the output of the script to be a JSON-serializable object (h/t to Michael Case from the comments section).
Furthermore, the script is not indented properly. Python is an indentation-sensitive language, i.e. indentation matters.
Try something like this:
import datetime
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return {'date': str(next_third_thursday)}
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
|
show 2 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Zapier expects the output of the script to be a JSON-serializable object (h/t to Michael Case from the comments section).
Furthermore, the script is not indented properly. Python is an indentation-sensitive language, i.e. indentation matters.
Try something like this:
import datetime
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return {'date': str(next_third_thursday)}
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
|
show 2 more comments
2
Zapier expects the output of the script to be a JSON-serializable object (h/t to Michael Case from the comments section).
Furthermore, the script is not indented properly. Python is an indentation-sensitive language, i.e. indentation matters.
Try something like this:
import datetime
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return {'date': str(next_third_thursday)}
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
|
show 2 more comments
2
2
2
Zapier expects the output of the script to be a JSON-serializable object (h/t to Michael Case from the comments section).
Furthermore, the script is not indented properly. Python is an indentation-sensitive language, i.e. indentation matters.
Try something like this:
import datetime
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return {'date': str(next_third_thursday)}
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
Zapier expects the output of the script to be a JSON-serializable object (h/t to Michael Case from the comments section).
Furthermore, the script is not indented properly. Python is an indentation-sensitive language, i.e. indentation matters.
Try something like this:
import datetime
today = datetime.date.today()
next_thursday = today + datetime.timedelta(((3 - today.weekday()) % 7))
while True:
if 15 <= next_thursday.day <= 21:
next_third_thursday = next_thursday
break
else:
next_date = next_thursday + datetime.timedelta(days=1)
next_thursday = next_date + datetime.timedelta(((3 - next_date.weekday()) % 7))
return {'date': str(next_third_thursday)}
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
edited Jan 23 at 13:12
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
answered Jan 20 at 14:40
Milan CermakMilan Cermak
1,78611524
1,78611524
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
|
show 2 more comments
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
Ah. Unfortunately that returned the same error. :(
– Evan Cory Levine
Jan 20 at 14:55
1
1
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
I've updated the answer. I think you might also need to indent the code properly.
– Milan Cermak
Jan 20 at 15:24
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
silly me. I did indent the code but pasted it without the indentations by mistake. unfortunately... your updated answer still returns the same error. :( ugh. so frustrating.
– Evan Cory Levine
Jan 20 at 16:43
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
oh, and the error return just shows the code unindented, but it is properly indented when run.
– Evan Cory Levine
Jan 21 at 15:59
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
Milan's answer is close. The issue here is that json.dumps serializes your object converting it into a string. So in this example you are still returning a string which is why you are receiving the same error. With Zapier's code module you need to return a dictionary object which Zapier automatically maps to JSON format for use in later steps. In this case remove the json.dumps line and simply return the dictionary object.
– Michael Case
Jan 23 at 0:35
|
show 2 more comments
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