Reactor Scheduler with anonymous thread












0















I'm testing how reactor works, created such code which is quite similar to what can be found in reactor documentation.



import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
import reactor.core.publisher.Mono;
import reactor.core.scheduler.Scheduler;
import reactor.core.scheduler.Schedulers;

@SpringBootTest
@RunWith(SpringRunner.class)
public class ReactorApplicationTests {

@Test
public void publishOnThreadTest() {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe(System.out::println)).start();
}
}


And I cannot make it run, what am I doing wrong? With just subscribe it works but I wanted to look at thread used and play a bit with it.










share|improve this question




















  • 1





    1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

    – Alexei Kaigorodov
    Jan 20 at 11:09











  • By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

    – ppysz
    Jan 20 at 11:18
















0















I'm testing how reactor works, created such code which is quite similar to what can be found in reactor documentation.



import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
import reactor.core.publisher.Mono;
import reactor.core.scheduler.Scheduler;
import reactor.core.scheduler.Schedulers;

@SpringBootTest
@RunWith(SpringRunner.class)
public class ReactorApplicationTests {

@Test
public void publishOnThreadTest() {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe(System.out::println)).start();
}
}


And I cannot make it run, what am I doing wrong? With just subscribe it works but I wanted to look at thread used and play a bit with it.










share|improve this question




















  • 1





    1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

    – Alexei Kaigorodov
    Jan 20 at 11:09











  • By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

    – ppysz
    Jan 20 at 11:18














0












0








0








I'm testing how reactor works, created such code which is quite similar to what can be found in reactor documentation.



import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
import reactor.core.publisher.Mono;
import reactor.core.scheduler.Scheduler;
import reactor.core.scheduler.Schedulers;

@SpringBootTest
@RunWith(SpringRunner.class)
public class ReactorApplicationTests {

@Test
public void publishOnThreadTest() {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe(System.out::println)).start();
}
}


And I cannot make it run, what am I doing wrong? With just subscribe it works but I wanted to look at thread used and play a bit with it.










share|improve this question
















I'm testing how reactor works, created such code which is quite similar to what can be found in reactor documentation.



import org.junit.Test;
import org.junit.runner.RunWith;
import org.springframework.boot.test.context.SpringBootTest;
import org.springframework.test.context.junit4.SpringRunner;
import reactor.core.publisher.Mono;
import reactor.core.scheduler.Scheduler;
import reactor.core.scheduler.Schedulers;

@SpringBootTest
@RunWith(SpringRunner.class)
public class ReactorApplicationTests {

@Test
public void publishOnThreadTest() {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe(System.out::println)).start();
}
}


And I cannot make it run, what am I doing wrong? With just subscribe it works but I wanted to look at thread used and play a bit with it.







java multithreading project-reactor reactor






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 20 at 12:35









Gonzalo Matheu

3,36332132




3,36332132










asked Jan 20 at 9:35









ppyszppysz

133116




133116








  • 1





    1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

    – Alexei Kaigorodov
    Jan 20 at 11:09











  • By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

    – ppysz
    Jan 20 at 11:18














  • 1





    1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

    – Alexei Kaigorodov
    Jan 20 at 11:09











  • By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

    – ppysz
    Jan 20 at 11:18








1




1





1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

– Alexei Kaigorodov
Jan 20 at 11:09





1. "I cannot make it run" - what happens? 2. Add import statement so we could reproduce the behaviour.

– Alexei Kaigorodov
Jan 20 at 11:09













By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

– ppysz
Jan 20 at 11:18





By I cannot run this i mean there is nothing printed as result. It works with above subscribe being outside of new Thread.

– ppysz
Jan 20 at 11:18












1 Answer
1






active

oldest

votes


















2














The reason your test program prints nothing is because it exits too early. It should wait until substriber's method is called:



@Test
public void publishOnThreadTest() throws InterruptedException {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);
CountDownLatch latch = new CountDownLatch(1);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe((String str) ->{
System.out.println(str);
latch.countDown();
})).start();

latch.await();
}





share|improve this answer
























  • Thank you very much!

    – ppysz
    Jan 20 at 12:28











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














The reason your test program prints nothing is because it exits too early. It should wait until substriber's method is called:



@Test
public void publishOnThreadTest() throws InterruptedException {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);
CountDownLatch latch = new CountDownLatch(1);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe((String str) ->{
System.out.println(str);
latch.countDown();
})).start();

latch.await();
}





share|improve this answer
























  • Thank you very much!

    – ppysz
    Jan 20 at 12:28
















2














The reason your test program prints nothing is because it exits too early. It should wait until substriber's method is called:



@Test
public void publishOnThreadTest() throws InterruptedException {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);
CountDownLatch latch = new CountDownLatch(1);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe((String str) ->{
System.out.println(str);
latch.countDown();
})).start();

latch.await();
}





share|improve this answer
























  • Thank you very much!

    – ppysz
    Jan 20 at 12:28














2












2








2







The reason your test program prints nothing is because it exits too early. It should wait until substriber's method is called:



@Test
public void publishOnThreadTest() throws InterruptedException {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);
CountDownLatch latch = new CountDownLatch(1);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe((String str) ->{
System.out.println(str);
latch.countDown();
})).start();

latch.await();
}





share|improve this answer













The reason your test program prints nothing is because it exits too early. It should wait until substriber's method is called:



@Test
public void publishOnThreadTest() throws InterruptedException {
Scheduler s = Schedulers.newParallel("parallel-scheduler", 4);
CountDownLatch latch = new CountDownLatch(1);

final Mono<String> mono = Mono.just("Publish on test: n")
.map(msg -> msg + "before: " + Thread.currentThread() )
.publishOn(s)
.map(msg -> msg + "nafter: " + Thread.currentThread());

new Thread(() -> mono.subscribe((String str) ->{
System.out.println(str);
latch.countDown();
})).start();

latch.await();
}






share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 20 at 12:20









Alexei KaigorodovAlexei Kaigorodov

10.1k11029




10.1k11029













  • Thank you very much!

    – ppysz
    Jan 20 at 12:28



















  • Thank you very much!

    – ppysz
    Jan 20 at 12:28

















Thank you very much!

– ppysz
Jan 20 at 12:28





Thank you very much!

– ppysz
Jan 20 at 12:28




















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