Difference in AWK when using NR with and withou print
I am a AWK beginner and after playing around with the built-in variable NR, I do not understand the following
Text:
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
using
awk 'NR' file
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR}' file
1
2
3
4
Thus, I was expecting to the same results when using NR>2&&NR<5. Here is what I got:
awk 'NR>2&&NR<5' file
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR>2&&NR<5}' file
Nothing shows up
Could you tell me why isn´t the last line showing a count from the numbers to 3 to 4 as it is displayed when using awk '{print NR}' file? It is not possible to mix a range of NR with the command print?
Thanks in advance!
awk text-processing text-parsing
edited Jan 19 at 10:27
Inian
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
add a comment |
I am a AWK beginner and after playing around with the built-in variable NR, I do not understand the following
Text:
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
using
awk 'NR' file
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR}' file
1
2
3
4
Thus, I was expecting to the same results when using NR>2&&NR<5. Here is what I got:
awk 'NR>2&&NR<5' file
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR>2&&NR<5}' file
Nothing shows up
Could you tell me why isn´t the last line showing a count from the numbers to 3 to 4 as it is displayed when using awk '{print NR}' file? It is not possible to mix a range of NR with the command print?
Thanks in advance!
awk text-processing text-parsing
edited Jan 19 at 10:27
Inian
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
1
Hint: tryawk '{print (NR>2&&NR<5)}' fileandawk 'NR>2&&NR<5 {print NR}' file.
– Gordon Davisson
Jan 19 at 9:27
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writingprint ( (NR>2) && (NR<5) )instead ofprint NR>2&&NR<5and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).
– Ed Morton
Jan 19 at 20:55
add a comment |
I am a AWK beginner and after playing around with the built-in variable NR, I do not understand the following
Text:
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
using
awk 'NR' file
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR}' file
1
2
3
4
Thus, I was expecting to the same results when using NR>2&&NR<5. Here is what I got:
awk 'NR>2&&NR<5' file
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR>2&&NR<5}' file
Nothing shows up
Could you tell me why isn´t the last line showing a count from the numbers to 3 to 4 as it is displayed when using awk '{print NR}' file? It is not possible to mix a range of NR with the command print?
Thanks in advance!
awk text-processing text-parsing
edited Jan 19 at 10:27
Inian
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
I am a AWK beginner and after playing around with the built-in variable NR, I do not understand the following
Text:
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
using
awk 'NR' file
CREDITS,EXPDATE,USER,GROUPS
99,01 jun 2018,sylvain,team:::admin
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR}' file
1
2
3
4
Thus, I was expecting to the same results when using NR>2&&NR<5. Here is what I got:
awk 'NR>2&&NR<5' file
52,01 dec 2018,sonia,team
52,01 dec 2018,sonia,team
awk '{print NR>2&&NR<5}' file
Nothing shows up
Could you tell me why isn´t the last line showing a count from the numbers to 3 to 4 as it is displayed when using awk '{print NR}' file? It is not possible to mix a range of NR with the command print?
Thanks in advance!
awk text-processing text-parsing
awk text-processing text-parsing
edited Jan 19 at 10:27
Inian
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
edited Jan 19 at 10:27
Inian
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
edited Jan 19 at 10:27
Inian
39.3k63971
edited Jan 19 at 10:27
Inian
39.3k63971
edited Jan 19 at 10:27
Inian
39.3k63971
39.3k63971
asked Jan 19 at 9:21
little_micelittle_mice
163
asked Jan 19 at 9:21
little_micelittle_mice
163
asked Jan 19 at 9:21
little_micelittle_mice
163
163
1
Hint: tryawk '{print (NR>2&&NR<5)}' fileandawk 'NR>2&&NR<5 {print NR}' file.
– Gordon Davisson
Jan 19 at 9:27
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writingprint ( (NR>2) && (NR<5) )instead ofprint NR>2&&NR<5and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).
– Ed Morton
Jan 19 at 20:55
add a comment |
1
Hint: tryawk '{print (NR>2&&NR<5)}' fileandawk 'NR>2&&NR<5 {print NR}' file.
– Gordon Davisson
Jan 19 at 9:27
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writingprint ( (NR>2) && (NR<5) )instead ofprint NR>2&&NR<5and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).
– Ed Morton
Jan 19 at 20:55
1
1
Hint: try
awk '{print (NR>2&&NR<5)}' file and awk 'NR>2&&NR<5 {print NR}' file.– Gordon Davisson
Jan 19 at 9:27
Hint: try
awk '{print (NR>2&&NR<5)}' file and awk 'NR>2&&NR<5 {print NR}' file.– Gordon Davisson
Jan 19 at 9:27
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writing
print ( (NR>2) && (NR<5) ) instead of print NR>2&&NR<5 and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).– Ed Morton
Jan 19 at 20:55
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writing
print ( (NR>2) && (NR<5) ) instead of print NR>2&&NR<5 and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).– Ed Morton
Jan 19 at 20:55
add a comment |
1 Answer
1
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oldest
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awk 'NR>2&&NR<5' Input_file is where we are checking condition if line number is greater than 2 and greater than 5 then do default action which is printing current line.
In you code awk '{print NR>2&&NR<5}' Input_file, here you are using print and then mentioning condition which is NOT the way awk works.
awk works on method of:
Condition_check/regexp{action}
if NO action is given then by default print of current line will happen, which is happening in your first code.
More analysis:
To prove point {print NR>2&&NR<5} will NOT behave like default method of awk of regexp/condition_check{action} run this:
awk '{print (NR>2&&NR<5)}' Input_file
See the output what it will provide:
0
0
1
1
0
0
0
0
0
0
See line 3rd and 4th which is 1 means condition for that line is TRUE and 0 means condition for that line is FALSE. So by this we could see it prints condition's STATE in print statement if we use condition in (..) like mentioned above.
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
add a comment |
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awk 'NR>2&&NR<5' Input_file is where we are checking condition if line number is greater than 2 and greater than 5 then do default action which is printing current line.
In you code awk '{print NR>2&&NR<5}' Input_file, here you are using print and then mentioning condition which is NOT the way awk works.
awk works on method of:
Condition_check/regexp{action}
if NO action is given then by default print of current line will happen, which is happening in your first code.
More analysis:
To prove point {print NR>2&&NR<5} will NOT behave like default method of awk of regexp/condition_check{action} run this:
awk '{print (NR>2&&NR<5)}' Input_file
See the output what it will provide:
0
0
1
1
0
0
0
0
0
0
See line 3rd and 4th which is 1 means condition for that line is TRUE and 0 means condition for that line is FALSE. So by this we could see it prints condition's STATE in print statement if we use condition in (..) like mentioned above.
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
add a comment |
awk 'NR>2&&NR<5' Input_file is where we are checking condition if line number is greater than 2 and greater than 5 then do default action which is printing current line.
In you code awk '{print NR>2&&NR<5}' Input_file, here you are using print and then mentioning condition which is NOT the way awk works.
awk works on method of:
Condition_check/regexp{action}
if NO action is given then by default print of current line will happen, which is happening in your first code.
More analysis:
To prove point {print NR>2&&NR<5} will NOT behave like default method of awk of regexp/condition_check{action} run this:
awk '{print (NR>2&&NR<5)}' Input_file
See the output what it will provide:
0
0
1
1
0
0
0
0
0
0
See line 3rd and 4th which is 1 means condition for that line is TRUE and 0 means condition for that line is FALSE. So by this we could see it prints condition's STATE in print statement if we use condition in (..) like mentioned above.
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
add a comment |
awk 'NR>2&&NR<5' Input_file is where we are checking condition if line number is greater than 2 and greater than 5 then do default action which is printing current line.
In you code awk '{print NR>2&&NR<5}' Input_file, here you are using print and then mentioning condition which is NOT the way awk works.
awk works on method of:
Condition_check/regexp{action}
if NO action is given then by default print of current line will happen, which is happening in your first code.
More analysis:
To prove point {print NR>2&&NR<5} will NOT behave like default method of awk of regexp/condition_check{action} run this:
awk '{print (NR>2&&NR<5)}' Input_file
See the output what it will provide:
0
0
1
1
0
0
0
0
0
0
See line 3rd and 4th which is 1 means condition for that line is TRUE and 0 means condition for that line is FALSE. So by this we could see it prints condition's STATE in print statement if we use condition in (..) like mentioned above.
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
awk 'NR>2&&NR<5' Input_file is where we are checking condition if line number is greater than 2 and greater than 5 then do default action which is printing current line.
In you code awk '{print NR>2&&NR<5}' Input_file, here you are using print and then mentioning condition which is NOT the way awk works.
awk works on method of:
Condition_check/regexp{action}
if NO action is given then by default print of current line will happen, which is happening in your first code.
More analysis:
To prove point {print NR>2&&NR<5} will NOT behave like default method of awk of regexp/condition_check{action} run this:
awk '{print (NR>2&&NR<5)}' Input_file
See the output what it will provide:
0
0
1
1
0
0
0
0
0
0
See line 3rd and 4th which is 1 means condition for that line is TRUE and 0 means condition for that line is FALSE. So by this we could see it prints condition's STATE in print statement if we use condition in (..) like mentioned above.
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
edited Jan 19 at 12:59
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
answered Jan 19 at 9:52
RavinderSingh13RavinderSingh13
27.2k41438
27.2k41438
add a comment |
add a comment |
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1
Hint: try
awk '{print (NR>2&&NR<5)}' fileandawk 'NR>2&&NR<5 {print NR}' file.– Gordon Davisson
Jan 19 at 9:27
Hello Gordon. The first attempt gave some strange results, a couple of zeros and ones, whereas the second attempt perfectly printed what I was looking for. Could you explain to me why you have to use NR again when using {print}? In the first example I didn´t have to use it in order to simply get my numbers, so why does it have to use in this case?
– little_mice
Jan 19 at 9:36
You might want to invest in some white space a parentheses when writing code. It makes your code clearer and less error prone. Try writing
print ( (NR>2) && (NR<5) )instead ofprint NR>2&&NR<5and notice the difference in both functionality and clarity (what you currently have should really be flagged as a syntax error but it's also undefined behavior so YMMV).– Ed Morton
Jan 19 at 20:55