MongoDB Convert Array of Objects to Single Object












2















Using a MongoDB aggregate query, how do I convert an array of documents to a single document. The array can have N number of documents.



Before



"loop" : [
{
"field1" : "1"
},
{
"field2" : "2",
"field3" : "3",
},
{
"field4" : "4",
},
{
"field5" : "5",
"field6" : "6"
}
]


After



"loop" : {
"field1" : "1",
"field2" : "2",
"field3" : "3",
"field4" : "4",
"field5" : "5",
"field6" : "6"
}









share|improve this question





























    2















    Using a MongoDB aggregate query, how do I convert an array of documents to a single document. The array can have N number of documents.



    Before



    "loop" : [
    {
    "field1" : "1"
    },
    {
    "field2" : "2",
    "field3" : "3",
    },
    {
    "field4" : "4",
    },
    {
    "field5" : "5",
    "field6" : "6"
    }
    ]


    After



    "loop" : {
    "field1" : "1",
    "field2" : "2",
    "field3" : "3",
    "field4" : "4",
    "field5" : "5",
    "field6" : "6"
    }









    share|improve this question



























      2












      2








      2


      1






      Using a MongoDB aggregate query, how do I convert an array of documents to a single document. The array can have N number of documents.



      Before



      "loop" : [
      {
      "field1" : "1"
      },
      {
      "field2" : "2",
      "field3" : "3",
      },
      {
      "field4" : "4",
      },
      {
      "field5" : "5",
      "field6" : "6"
      }
      ]


      After



      "loop" : {
      "field1" : "1",
      "field2" : "2",
      "field3" : "3",
      "field4" : "4",
      "field5" : "5",
      "field6" : "6"
      }









      share|improve this question
















      Using a MongoDB aggregate query, how do I convert an array of documents to a single document. The array can have N number of documents.



      Before



      "loop" : [
      {
      "field1" : "1"
      },
      {
      "field2" : "2",
      "field3" : "3",
      },
      {
      "field4" : "4",
      },
      {
      "field5" : "5",
      "field6" : "6"
      }
      ]


      After



      "loop" : {
      "field1" : "1",
      "field2" : "2",
      "field3" : "3",
      "field4" : "4",
      "field5" : "5",
      "field6" : "6"
      }






      mongodb aggregation-framework






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 19 at 16:13







      Aydus-Matthew

















      asked Jan 19 at 2:33









      Aydus-MatthewAydus-Matthew

      1,25811933




      1,25811933
























          2 Answers
          2






          active

          oldest

          votes


















          2














          You can use below aggregation in 3.6 and above.



          db.colname.aggregate(
          [{"$project":{
          "loop":{
          "$reduce":{
          "input":"$loop",
          "initialValue":{},
          "in":{"$mergeObjects":["$$value","$$this"]
          }
          }
          }
          }}]
          )





          share|improve this answer































            1














            Based on Veeram's answer above using $mergeObjects, here's a more concise query using $project.



            Query



            db.loop.aggregate(
            [{
            "$project": {
            "loop": { $mergeObjects: "$loop" }
            }
            }]
            )


            Result



            { 
            "loop" : {
            "field1" : "1",
            "field2" : "2",
            "field3" : "3",
            "field4" : "4",
            "field5" : "5",
            "field6" : "6"
            }
            }





            share|improve this answer























              Your Answer






              StackExchange.ifUsing("editor", function () {
              StackExchange.using("externalEditor", function () {
              StackExchange.using("snippets", function () {
              StackExchange.snippets.init();
              });
              });
              }, "code-snippets");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "1"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });














              draft saved

              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54263619%2fmongodb-convert-array-of-objects-to-single-object%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              2














              You can use below aggregation in 3.6 and above.



              db.colname.aggregate(
              [{"$project":{
              "loop":{
              "$reduce":{
              "input":"$loop",
              "initialValue":{},
              "in":{"$mergeObjects":["$$value","$$this"]
              }
              }
              }
              }}]
              )





              share|improve this answer




























                2














                You can use below aggregation in 3.6 and above.



                db.colname.aggregate(
                [{"$project":{
                "loop":{
                "$reduce":{
                "input":"$loop",
                "initialValue":{},
                "in":{"$mergeObjects":["$$value","$$this"]
                }
                }
                }
                }}]
                )





                share|improve this answer


























                  2












                  2








                  2







                  You can use below aggregation in 3.6 and above.



                  db.colname.aggregate(
                  [{"$project":{
                  "loop":{
                  "$reduce":{
                  "input":"$loop",
                  "initialValue":{},
                  "in":{"$mergeObjects":["$$value","$$this"]
                  }
                  }
                  }
                  }}]
                  )





                  share|improve this answer













                  You can use below aggregation in 3.6 and above.



                  db.colname.aggregate(
                  [{"$project":{
                  "loop":{
                  "$reduce":{
                  "input":"$loop",
                  "initialValue":{},
                  "in":{"$mergeObjects":["$$value","$$this"]
                  }
                  }
                  }
                  }}]
                  )






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Jan 19 at 3:33









                  VeeramVeeram

                  39.8k33458




                  39.8k33458

























                      1














                      Based on Veeram's answer above using $mergeObjects, here's a more concise query using $project.



                      Query



                      db.loop.aggregate(
                      [{
                      "$project": {
                      "loop": { $mergeObjects: "$loop" }
                      }
                      }]
                      )


                      Result



                      { 
                      "loop" : {
                      "field1" : "1",
                      "field2" : "2",
                      "field3" : "3",
                      "field4" : "4",
                      "field5" : "5",
                      "field6" : "6"
                      }
                      }





                      share|improve this answer




























                        1














                        Based on Veeram's answer above using $mergeObjects, here's a more concise query using $project.



                        Query



                        db.loop.aggregate(
                        [{
                        "$project": {
                        "loop": { $mergeObjects: "$loop" }
                        }
                        }]
                        )


                        Result



                        { 
                        "loop" : {
                        "field1" : "1",
                        "field2" : "2",
                        "field3" : "3",
                        "field4" : "4",
                        "field5" : "5",
                        "field6" : "6"
                        }
                        }





                        share|improve this answer


























                          1












                          1








                          1







                          Based on Veeram's answer above using $mergeObjects, here's a more concise query using $project.



                          Query



                          db.loop.aggregate(
                          [{
                          "$project": {
                          "loop": { $mergeObjects: "$loop" }
                          }
                          }]
                          )


                          Result



                          { 
                          "loop" : {
                          "field1" : "1",
                          "field2" : "2",
                          "field3" : "3",
                          "field4" : "4",
                          "field5" : "5",
                          "field6" : "6"
                          }
                          }





                          share|improve this answer













                          Based on Veeram's answer above using $mergeObjects, here's a more concise query using $project.



                          Query



                          db.loop.aggregate(
                          [{
                          "$project": {
                          "loop": { $mergeObjects: "$loop" }
                          }
                          }]
                          )


                          Result



                          { 
                          "loop" : {
                          "field1" : "1",
                          "field2" : "2",
                          "field3" : "3",
                          "field4" : "4",
                          "field5" : "5",
                          "field6" : "6"
                          }
                          }






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Jan 19 at 16:23









                          Aydus-MatthewAydus-Matthew

                          1,25811933




                          1,25811933






























                              draft saved

                              draft discarded




















































                              Thanks for contributing an answer to Stack Overflow!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54263619%2fmongodb-convert-array-of-objects-to-single-object%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown