socket listener client in multiprocessing didn't exit
Want to write a socket client with multiprocessing, any idea what's wrong the following code?
I don't have to write the server in python however I need to generate a free port on the localhost before listening. The port is sent to the server in other code.
Also I am expecting the following code to print out message every 1 secs for debugging purpose, but it only print out once. And the process didn't join even after I set the stop event.
def getsocket():
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('', 0))
return s
except Exception as err:
return None
def PortListener(s, stopper):
print("Listensing to port for message")
while not stopper.is_set():
time.sleep(1)
print("check message..")
message = s.recv(4096)
if message:
print("received message: {}".format(message))
def logprogress():
s = getsocket()
port = s.getsockname()[1]
print("port number: {}".format(str(port)))
s.connect(("localhost", port))
stopper = mp.Event()
logger = mp.Process(target=PortListener, args=(s, stopper))
logger.start()
return logger, stopper
def stopprogress(logger, stopper):
if logger and stopper:
print("Stopping listening to worker's progress.")
stopper.set()
logger.join()
print("Exit process")
else:
raise TypeError
if __name__ == '__main__':
logger, stopper = logprogress()
time.sleep(10)
stopprogress(logger, stopper)
python sockets multiprocessing
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
add a comment |
Want to write a socket client with multiprocessing, any idea what's wrong the following code?
I don't have to write the server in python however I need to generate a free port on the localhost before listening. The port is sent to the server in other code.
Also I am expecting the following code to print out message every 1 secs for debugging purpose, but it only print out once. And the process didn't join even after I set the stop event.
def getsocket():
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('', 0))
return s
except Exception as err:
return None
def PortListener(s, stopper):
print("Listensing to port for message")
while not stopper.is_set():
time.sleep(1)
print("check message..")
message = s.recv(4096)
if message:
print("received message: {}".format(message))
def logprogress():
s = getsocket()
port = s.getsockname()[1]
print("port number: {}".format(str(port)))
s.connect(("localhost", port))
stopper = mp.Event()
logger = mp.Process(target=PortListener, args=(s, stopper))
logger.start()
return logger, stopper
def stopprogress(logger, stopper):
if logger and stopper:
print("Stopping listening to worker's progress.")
stopper.set()
logger.join()
print("Exit process")
else:
raise TypeError
if __name__ == '__main__':
logger, stopper = logprogress()
time.sleep(10)
stopprogress(logger, stopper)
python sockets multiprocessing
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
add a comment |
Want to write a socket client with multiprocessing, any idea what's wrong the following code?
I don't have to write the server in python however I need to generate a free port on the localhost before listening. The port is sent to the server in other code.
Also I am expecting the following code to print out message every 1 secs for debugging purpose, but it only print out once. And the process didn't join even after I set the stop event.
def getsocket():
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('', 0))
return s
except Exception as err:
return None
def PortListener(s, stopper):
print("Listensing to port for message")
while not stopper.is_set():
time.sleep(1)
print("check message..")
message = s.recv(4096)
if message:
print("received message: {}".format(message))
def logprogress():
s = getsocket()
port = s.getsockname()[1]
print("port number: {}".format(str(port)))
s.connect(("localhost", port))
stopper = mp.Event()
logger = mp.Process(target=PortListener, args=(s, stopper))
logger.start()
return logger, stopper
def stopprogress(logger, stopper):
if logger and stopper:
print("Stopping listening to worker's progress.")
stopper.set()
logger.join()
print("Exit process")
else:
raise TypeError
if __name__ == '__main__':
logger, stopper = logprogress()
time.sleep(10)
stopprogress(logger, stopper)
python sockets multiprocessing
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
Want to write a socket client with multiprocessing, any idea what's wrong the following code?
I don't have to write the server in python however I need to generate a free port on the localhost before listening. The port is sent to the server in other code.
Also I am expecting the following code to print out message every 1 secs for debugging purpose, but it only print out once. And the process didn't join even after I set the stop event.
def getsocket():
try:
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('', 0))
return s
except Exception as err:
return None
def PortListener(s, stopper):
print("Listensing to port for message")
while not stopper.is_set():
time.sleep(1)
print("check message..")
message = s.recv(4096)
if message:
print("received message: {}".format(message))
def logprogress():
s = getsocket()
port = s.getsockname()[1]
print("port number: {}".format(str(port)))
s.connect(("localhost", port))
stopper = mp.Event()
logger = mp.Process(target=PortListener, args=(s, stopper))
logger.start()
return logger, stopper
def stopprogress(logger, stopper):
if logger and stopper:
print("Stopping listening to worker's progress.")
stopper.set()
logger.join()
print("Exit process")
else:
raise TypeError
if __name__ == '__main__':
logger, stopper = logprogress()
time.sleep(10)
stopprogress(logger, stopper)
python sockets multiprocessing
python sockets multiprocessing
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
asked Jan 19 at 6:10
Jie ZhangJie Zhang
357
357
add a comment |
add a comment |
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